[英]MySQL query to fetch all products and its category
我正在嘗試獲取產品,並將相關類別作為逗號分隔的列表。 以下是我嘗試過的方法,但僅返回1種產品。 我嘗試了LEFT和LEFT OUTER連接,但是都沒有用。 有任何想法嗎?
SELECT 'U' as ACTION
, product_id
, GROUP_CONCAT(PC.category_id SEPARATOR ', ') as Categories
FROM Products P LEFT JOIN Product_Category PC
ON PC.product_id = P.product_id
添加分組依據
SELECT 'U' as ACTION, product_id, GROUP_CONCAT(PC.category_id SEPARATOR ', ') as Categories
FROM Products P LEFT JOIN Product_Category PC
ON PC.product_id = P.product_id group by P.product_id;
-----------------示例-----------
select * from calls;
+----+------------+---------+
| id | date | user_id |
+----+------------+---------+
| 1 | 2016-06-22 | 1 |
| 2 | 2016-06-22 | NULL |
| 3 | 2016-06-22 | NULL |
| 4 | 2016-06-23 | 2 |
| 5 | 2016-06-23 | 1 |
| 6 | 2016-06-23 | 1 |
| 7 | 2016-06-23 | NULL |
+----+------------+---------+
7 rows in set (0.03 sec)
mysql> select * from payments;
+----+------------+---------+-------+
| id | date | user_id | value |
+----+------------+---------+-------+
| 1 | 2016-06-22 | 1 | 10 |
| 2 | 2016-06-22 | 3 | 15 |
| 3 | 2016-06-22 | 4 | 20 |
| 4 | 2016-06-23 | 2 | 100 |
| 5 | 2016-06-23 | 1 | 150 |
+----+------------+---------+-------+
5 rows in set (0.00 sec)
mysql> select c.user_id,group_concat(p.value) from calls c inner join payments p on p.user_id=c.user_id group by c.user_id;
+---------+-----------------------+
| user_id | group_concat(p.value) |
+---------+-----------------------+
| 1 | 10,150,10,150,10,150 |
| 2 | 100 |
+---------+-----------------------+
2 rows in set (0.00 sec)
GROUP_CONCAT
函數是一個聚合函數,並且正在使用GROUP BY
子句。 如果SELECT
語句中沒有GROUP BY
,則它將使用所有找到的結果。
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