使用 Spring 從存儲庫中獲取數據

Question

好的，所以我是春天的新手，並不真正知道這是如何工作的。 我一直在嘗試一些事情，並認為它接近完成但沒有從服務器獲取任何數據並給我這個錯誤

 Unsatisfied dependency expressed through constructor argument with index 4 of type [jp.co.fusionsystems.dimare.crm.service.impl.MyDataDefaultService]: : Error creating bean with name 'MyDataDefaultService' defined in file  

我的終點

//mobile data endpoint
 @RequestMapping(
        value = API_PREFIX + ENDPOINT_MyData + "/getMyData",
        method = RequestMethod.GET)
public MyData getMyData() {
    return MyDataDefaultService.getData();
}

我的對象

public class MyData {

public MyData(final Builder builder) {
    videoLink = builder.videoLink;
}
private String videoLink;

public String getVideoLink()
{
    return videoLink;
}

public static class Builder
{
    private String videoLink = "";  

    public Builder setVideo(String videoLink)
    {
        this.videoLink = videoLink;
        return this;
    }

    public MyData build()
    {
        return new MyData(this);
    }

}
 @Override
    public boolean equals(final Object other) {
        return ObjectUtils.equals(this, other);
    }

    @Override
    public int hashCode() {
        return ObjectUtils.hashCode(this);
    }

    @Override
    public String toString() {
        return ObjectUtils.toString(this);
    }

    }

存儲庫

 public classMyServerMyDataRepository implements MyDataRepository{

private finalMyServerMyDataJpaRepository jpaRepository;
private final MyDataConverter MyDataConverter = new MyDataConverter();

@Autowired
publicMyServerMyDataRepository(finalMyServerMyDataJpaRepository jpaRepository) {
    this.jpaRepository = Validate.notNull(jpaRepository);
}


@Override
public MyData getData() {
    MyDataEntity entity = jpaRepository.findOne((long) 0);
    MyData.Builder builder = new MyData.Builder()
            .setVideo(entity.getVideoLink());

    return builder.build();
}

端點調用的 DefaultService

 public class MyDataDefaultService {
private static final Logger logger =      LoggerFactory.getLogger(NotificationDefaultService.class);

private finalMyServerMyDataRepository repository;

@Autowired
public MyDataDefaultService(MyServerMyDataRepository repository) {
    this.repository = Validate.notNull(repository);
}


//Get the data from the server
public MobileData getData()
{
    logger.info("Get Mobile Data from the server");
    //Get the data from the repository
    MobileData mobileData = repository.getData();

    return mobileData;

}
 }

轉換器

 public class MyDataConverter  extends AbstractConverter<MyDataEntity, MyData>
 {

@Override
public MyData convert(MyDataEntity entity) {

    MyData.Builder builder = new MyData.Builder()
            .setVideo(entity.getVideoLink());
    return builder.build();
}

 }

我的實體

 @Entity
 @Table(name = “myServer”)
 public class MyDataEntity extends AbstractEntity{
 @Column(name = "video_link", nullable = true)
    private String videoLink;

 public String getVideoLink() {
        return videoLink;
    }

    public void setVideoLink(final String videoLink) {
        this.videoLink = videoLink;
    }

}

感謝您對此的任何幫助

Answer 1

Hibernate 實體應該定義默認構造函數並實現Serializable接口，假設AbstractEntity符合要求。 Hibernate 不會接受沒有主鍵的實體，因此您也必須定義一個：

 @Entity
 @Table(name = “myServer”)
 public class MyDataEntity implements Serializable {

    @Id
    @GeneratedValue
    private Long id;

    @Column(name = "video_link", nullable = true)
    private String videoLink;

    public MyDataEntity() {

    }

    ...setters&getters
}

MyData對象表示 JSON 服務器響應，您可以使用Jackson注釋來控制結果 JSON 屬性：

public class MyDataResponse {

    @JsonProperty("video_link")
    private String videoLink;

    public MyDataResponse() {

    }

    public MyDataResponse(String videoLink) {
        this.videoLink = videoLink;
    }

    ...setters&getters
}

Spring 有一個很棒的項目，稱為Spring Data ，它提供了 JPA 存儲庫，因此甚至不需要@Repository注釋：

public class MyDataRepository extends CrudRepository<MyDataEntity, Long> {

}

Builder類代表服務層：

@Service
public class MyDataService {

    @Autowired
    private MyDataRepository myDataRepository;

    public MyDataResponse getMyData(Long id) {
        
        MyDataEntity entity = myDataRepository.findOne(id);
        ...rest logic, copy necessary data to MyDataResponse
    } 
}

那么控制器是：

@RestController // @ResponseBody not needed when using like this
public MyDataController {

    @Autowired
    private MyDataService myDataService;

    @RequestMapping("/getMyData") // no need to specify method for GET
    public MyDataResponse getMyData(@RequestParam("ID") Long myDataId) {
    
            ... validation logic
    
            return myDataService.getMyData(myDataId); // return response
    }
}

現在它應該可以工作了，不要忘記將所需的依賴項添加到您的類路徑中。