[英]where clause not working with like query
我有一個搜索查詢,當我搜索所有類似的關鍵字都可以正常工作時,記錄將顯示匹配的條件,但是問題是where子句不起作用。
$position = $this->session->set_userdata('position', $this->input->post('position'));
$adress_all = explode(",", $this->session->userdata('address'));
$this->db->like('address', $adress_all[0]);
$this->db->or_like('game', $this->session->userdata('skills'));
$this->db->or_like('gender', $this->session->userdata('coach'));
$this->db->or_like('Positions', $this->session->userdata('position'));
$this->db->where('type', 'private');//all other type coaches is also showing up
$sql = $this->db->get('coach');
您需要使用codeigniter的Grouping LIKE
$this->db->group_start();
$this->db->like('address', $adress_all[0]);
$this->db->or_like('game', $this->session->userdata('skills'));
$this->db->or_like('gender', $this->session->userdata('coach'));
$this->db->or_like('Positions', $this->session->userdata('position'));
$this->db->group_end();
$this->db->where('type', 'private');
$sql = $this->db->get('coach');
希望這行得通(需要在您的數據庫上進行測試)
嘗試下面的事情。
$this->db->where('type', 'private');//all other type coaches is also showing up
$this->db->where("(address LIKE '%". $adress_all[0]."%' OR game LIKE '%".$this->session->userdata('skills')."%' OR gender LIKE '%".$this->session->userdata('coach')."%' OR positions LIKE '%".$this->session->userdata('position')."%')",null,false);
$sql = $this->db->get('coach');
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