如何通過鐵軌交叉兩個ActiveRecord關系對象？

Question

我需要找到兩個ActiveRecord Relation對象的相交結果。 這是我的控制器

if params.has_key?(:car_insurance_type_id)
  car_insurance_type = CarInsuranceType.find_by(id: params[:car_insurance_type_id])
else
  car_insurance_type = CarInsuranceType.find_by(id: 1)
end

@breadcrumb_title = car_insurance_type.title

car_insurance_objects_private = car_insurance_type.car_insurance_objects

if params.has_key?(:car_model_id)
  car_model_search = CarModel.find_by(id: params[:car_model_id])

  if car_model_search
    car_insurance_objects_from_model = car_model_search.car_insurance_objects
  end

end

car_insurance_objects_private = car_insurance_objects_private & car_insurance_objects_from_model

但是“＆”方法不適用於ActiveRecord對象

這是我的模特

class CarInsuranceType < ActiveRecord::Base

  has_many :car_insurance_objects ,dependent: :destroy

end

class CarInsuranceObject < ActiveRecord::Base

  belongs_to :insurance_company
  belongs_to :car_insurance_type
  has_and_belongs_to_many :car_models

end

class CarModel < ActiveRecord::Base

  belongs_to :car_brand
  has_and_belongs_to_many :car_insurance_objects ,dependent: :destroy

end

那么，如何找到兩個屬於一個car_insurance_type的CarInsuranceObject和另一個具有has_and_belongs_to_many car_models的CarInsuranceObject之間的相交結果？

謝謝！

Answer 1

據我了解，你需要查詢數據庫的CarInsuranceObject “指定的第CarInsuranceType和CarModel 。 為什么不簡化所有這些東西：

car_insurance_type_id = params[:car_insurance_type_id] || 1
car_insurance_objects_private = car_model_search.car_insurance_objects.where(car_insurance_type_id: car_insurance_type_id)

順便說一句，變量確實有很長的名字。