[英]Snake movement javascript
我正在嘗試用js制作蛇游戲,我有這個移動代碼,其中sq正在移動DIV:
window.onkeyup = function move(e)
{
switch(e.keyCode)
{
case 37:
function moveLeft()
{
sq.style.left = parseInt(sq.style.left) - 20 + 'px';
checkGameOver();
}
setInterval(moveLeft, 500);
break;
case 38:
function moveUp()
{
sq.style.top = parseInt(sq.style.top) - 20 + 'px';
checkGameOver();
}
setInterval(moveUp, 500);
break;
case 39:
function moveRight()
{
sq.style.left = parseInt(sq.style.left) + 20 + 'px';
checkGameOver();
clearTimeout(timeLeft);
}
setInterval(moveRight, 500);
break;
case 40:
function moveDown()
{
sq.style.top = parseInt(sq.style.top) + 20 + 'px';
checkGameOver();
}
setInterval(moveDown, 500);
break;
}
}
但是任何時候我改變移動方向,最后方向停留並且移動不正確。 問題是如何才能使正確的運動以及如何阻止div?
在設置新間隔之前,將interval
分配給variable
並清除它:
var movementInterval;
window.onkeyup = function move(e)
{
if(movementInterval) {
clearInterval(movementInterval);
}
switch(e.keyCode)
{
case 37:
function moveLeft()
{
sq.style.left = parseInt(sq.style.left) - 20 + 'px';
checkGameOver();
}
movementInterval = setInterval(moveLeft, 500);
break;
case 38:
function moveUp()
{
sq.style.top = parseInt(sq.style.top) - 20 + 'px';
checkGameOver();
}
movementInterval = setInterval(moveUp, 500);
break;
case 39:
function moveRight()
{
sq.style.left = parseInt(sq.style.left) + 20 + 'px';
checkGameOver();
clearTimeout(timeLeft);
}
movementInterval = setInterval(moveRight, 500);
break;
case 40:
function moveDown()
{
sq.style.top = parseInt(sq.style.top) + 20 + 'px';
checkGameOver();
}
movementInterval = setInterval(moveDown, 500);
break;
}
}
否則,您將繼續使用每個按鍵創建新的intervals
。
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