Spring Security問題 - 404錯誤
[英]Spring Security issue - 404 error
問題描述
我只是想嘗試執行一個非常簡單的Spring安全示例項目但是我得到404錯誤。 請在這里幫助找到問題。
控制器：
package mypack;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller
public class SecurityController {
@RequestMapping(value = { "/", "/welcome**" }, method = RequestMethod.GET)
public ModelAndView welcomePage() {
ModelAndView model = new ModelAndView();
model.addObject("title", "Spring Security Hello World");
model.addObject("message", "This is welcome page!");
model.setViewName("hello");
return model;
}
@RequestMapping(value = "/admin**", method = RequestMethod.GET)
public ModelAndView adminPage() {
ModelAndView model = new ModelAndView();
model.addObject("title", "Spring Security Hello World");
model.addObject("message", "This is protected page!");
model.setViewName("admin");
return model;
}
}
為spring-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="mypack" />
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/views/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
彈簧security.xml文件
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.2.xsd">
<http auto-config="true">
<intercept-url pattern="/admin**" access="ROLE_USER" />
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="user" password="123456" authorities="ROLE_USER" />
</user-service>
</authentication-provider>
</authentication-manager>
web.xml中
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Spring MVC Application</display-name>
<!-- Spring MVC -->
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<!-- Loads Spring Security config file -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring-security.xml
</param-value>
</context-param>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
admin.jsp
<%@taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<%@page session="true"%>
<html>
<body>
<h1>Title : ${title}</h1>
<h1>Message : ${message}</h1>
<c:if test="${pageContext.request.userPrincipal.name != null}">
<h2>Welcome : ${pageContext.request.userPrincipal.name}
| <a href="<c:url value="/j_spring_security_logout" />" > Logout</a></h2>
</c:if>
為hello.jsp
<%@page session="false"%>
<html>
<body>
<h1>Title : ${title}</h1>
<h1>Message : ${message}</h1>
3 個解決方案
解決方案1
0 2016-07-05 10:57:36
在spring security xml文件中嘗試以下代碼。也可以根據您的要求更改角色。
<http auto-config="true" use-expressions="true">
<intercept-url pattern="/signin" access="permitAll"></intercept-url>
<intercept-url pattern="/logout" access="permitAll"></intercept-url>
<intercept-url pattern="/accessdenied" access="permitAll"></intercept-url>
<intercept-url method="GET" pattern="/**"
access="hasRole('USER')
or hasRole('ADMIN')"></intercept-url>
<form-login login-page="/signin" default-target-url="/index"
authentication-failure-url="/accessdenied" always-use-default-target="true"
username-parameter="username" password-parameter="password"></form-login>
<logout logout-success-url="/logout"></logout>
</http>
解決方案2
0 2016-07-05 11:05:15
正如您已在web.xml中將servlet映射配置為在servlet-mapping中將url-pattern配置為“/”。 因此，調度程序servlet將查找名為index.html / jsp的文件。
要配置控制器，必須將組件掃描添加到servlet.xml
添加以下行
<context:component-scan base-package="mypack" />
解決方案3
0 2016-07-05 12:42:51
您必須為路徑定義過濾器：
<intercept-url pattern="/" access="permitAll" />
<intercept-url pattern="/welcome" access="permitAll" />
因此，在這種情況下，沒有角色（匿名）的用戶可以訪問“/”和“/ welcome **”。
彈簧安全性404錯誤
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