使用JDBC驅動程序與Azure數據庫連接時發生錯誤

Question

與Azure數據庫連接時發生錯誤
2016年7月7日8:42:32 PM com.microsoft.sqlserver.jdbc.TDSChannel enableSSL信息：java.security路徑：C：\\ Program Files \\ Java \\ jdk1.8.0_60 \\ jre \\ lib \\ security安全提供程序：[SUN版本1.8，SunRsaSign版本1.8，SunEC版本1.8，SunJSSE版本1.8，SunJCE版本1.8，SunJGSS版本1.8，SunSASL版本1.8，XMLDSig版本1.8，SunPCSC版本1.8，SunMSCAPI版本1.8] SSLContext提供程序信息：Sun JSSE提供程序（PKCS12，SunX509 / PKIX密鑰/信任工廠，SSLv3 / TLSv1 / TLSv1.1 / TLSv1.2）SSLContext提供程序服務：[SunJSSE：KeyFactory.RSA-> sun.security.rsa.RSAKeyFactory別名：[1.2.840.113549.1.1，OID.1.2 .840.113549.1.1]，SunJSSE：KeyPairGenerator.RSA-> sun.security.rsa.RSAKeyPairGenerator別名：[1.2.840.113549.1.1，OID.1.2.840.113549.1.1]，SunJSSE：Signature.MD2withRSA-> sun.security.rsa .RSASignature $ MD2withRSA別名：[1.2.840.113549.1.1.2，OID.1.2.840.113549.1.1.2]，SunJSSE：Signature.MD5withRSA-> sun.security.rsa.RSASignature $ MD5withRSA別名：[1.2.840.113549.1 .1.4，OID.1.2.840.113549.1.1.4]，SunJSSE：Signature.SHA1withRSA-> sun.security.rsa.RSASignature $ SHA1withRSA別名：[1.2.840.113549.1.1.5，OID.1.2.840.113549.1.1.5 ，1.3.14.3.2.29，OID.1.3.14.3.2.29]，SunJSSE：Signature.MD5和SHA1withRSA-> sun.security.ssl.RSASignature，SunJSSE：KeyManagerFactory.SunX509-> sun.security.ssl.KeyManagerFactoryImpl $ SunX509，SunJSSE： KeyManagerFactory.NewSunX509-> sun.security.ssl.KeyManagerFactoryImpl $ X509別名：[PKIX]，SunJSSE：TrustManagerFactory.SunX509-> sun.security.ssl.TrustManagerFactoryImpl $ SimpleFactory，SunJSSE：TrustManagerFactory.PKIX-> sun.security.ssl。 TrustManagerFactoryImpl $ PKIXFactory別名：[SunPKIX，X509，X.509]，SunJSSE：SSLContext.TLSv1-> sun.security.ssl.SSLContextImpl $ TLS10Context別名：[SSLv3]，SunJSSE：SSLContext.TLSv1.1-> sun.security。 ssl.SSLContextImpl $ TLS11Context，SunJSSE：SSLContext.TLSv1.2-> sun.security.ssl.SSLContextImpl $ TLS12Context，SunJSSE：SSLContext.TLS-> sun.security.ssl.SSLContextImpl $ TLSCo ntext別名：[SSL]，SunJSSE：SSLContext.Default-> sun.security.ssl.SSLContextImpl $ DefaultSSLContext，SunJSSE：KeyStore.PKCS12-> sun.security.pkcs12.PKCS12KeyStore] java.ext.dirs：C：\\ Program Files \\ Java \\ jdk1.8.0_60 \\ jre \\ lib \\ ext; C：\\ WINDOWS \\ Sun \\ Java \\ lib \\ ext

使用的示例代碼

package UtilityCreateSensorData;
// Use the JDBC driver  
import java.sql.*;  
import com.microsoft.sqlserver.jdbc.*;  

public class SQLDatabaseConnection {

     // Connect to your database.  
    // Replace server name, username, and password with your credentials  
    public  void InsertData(String Value1,String Value2,String Value3,int Value4) {  

        String connectionString ="jdbc:sqlserver://test.database.windows.net:1433;database=test;user=TestUsername;password=TestPassword";  


        // Declare the JDBC objects.  
        Connection connection = null; 
        Statement statement = null;   
        ResultSet resultSet = null;  
        PreparedStatement prepsInsertProduct = null; 


        try {  
            connection = DriverManager.getConnection(connectionString); 
            // Create and execute an INSERT SQL prepared statement.  
           String insertSql = "INSERT INTO [dbo].[tblAutomationTest] (DESC,MessageStart,MessageEnd,SenseCount) VALUES " + "(Value1, Value2, Value3, Value4);";  

           prepsInsertProduct = connection.prepareStatement(insertSql, Statement.RETURN_GENERATED_KEYS);  
           prepsInsertProduct.execute();  

            // Retrieve the generated key from the insert.  
            resultSet = prepsInsertProduct.getGeneratedKeys();  

            // Print the ID of the inserted row.  
            while (resultSet.next()) { System.out.println("Generated: " + resultSet.getString(1));  
            }  

        }  
        catch (Exception e) {  
            e.printStackTrace();  
        }  
        finally {  
            if (connection != null) try { connection.close(); } catch(Exception e) {}
         // Close the connections after the data has been handled.  
            if (prepsInsertProduct != null) try { prepsInsertProduct.close(); } catch(Exception e) {}  
            if (resultSet != null) try { resultSet.close(); } catch(Exception e) {}  
            if (statement != null) try { statement.close(); } catch(Exception e) {}  
        }  
        }

}  

Answer 1

根據您的代碼，此問題是由於Azure SQL數據庫的連接字符串不正確引起的。

SQL Azure連接字符串的正確格式如下。

jdbc:sqlserver://<hostname>.database.windows.net:1433;database=<database-name>;user=<username>@<hostname>;password={your_password_here};encrypt=true;hostNameInCertificate=*.database.windows.net;loginTimeout=30;

您可以在Azure舊門戶上的選項卡DASHBOARD的右欄中Show connection strings的鏈接中找到它，也可以在Azure新門戶上的顯示數據庫連接字符串的鏈接中找到它。

您可以參考我對SO線程的答案如何使用JDBC連接到Azure SQL以查看圖和代碼，或參閱官方文章https://azure.microsoft.com/zh-cn/documentation/articles/sql- database-develop-java-simple / 。