在重復值最多的數組中顯示前5個值

Question

我想顯示前五個具有最多重復值的數組值，就像在標簽中一樣，我們在顯示流行的標簽，就像現在那樣，到目前為止，我正在從數據庫中獲取所有標簽，如下所示

SMS Gateway,sms service,bulk sms,bulk sms, Courier Management Software Development, Customised software solutions, domain registration, Ecommerce website designing company, matrimony website developer, seo tutorials bhopal, Web-site designing, redesigning, updationsSMS Gateway,sms service,bulk sms

然后將其分解為數組並以如下形式打印出來

 $tag = explode(",", $tags);

  $tagsss = array_count_values($tag);

    foreach($tagsss as $key => $value) {
      echo "<li>$key ( $value )</li>";
    }

結果顯示像這樣

SMS Gateway ( 1 )sms service ( 2 )bulk sms ( 3 ) Courier Management Software Development ( 1 ) Customised software solutions ( 1 ) domain registration ( 1 ) Ecommerce website designing company ( 1 ) matrimony website developer ( 1 ) seo tutorials bhopal ( 1 ) Web-site designing ( 1 ) redesigning ( 1 ) updationsSMS Gateway ( 1 )

現在，在所有此條目中，我只想顯示前五個值，它們與重復使用的標簽一樣，具有最重復的值

Answer 1

我將不使用PHP函數而是僅通過查詢從MySQL獲取這些標簽，例如

SELECT CONCAT( tag_name,  " ", COUNT( tag_name ) ) AS tags
FROM tags_table
GROUP BY tag_name
ORDER BY COUNT( tag_name ) DESC 
LIMIT 5