PHP Excel導出僅顯示MYsql表的最后一行

Question

我在使用模仿Excel文件的PHP腳本從MySQL數據庫導出數據時遇到問題。 數據僅導出MySQL表的最后一行。 我將代碼砍掉了，以刪除所有的關系查找（因為存在多個MySQL查詢，因此很難閱讀）。 我知道我已經寫完了變量，因此腳本只可以選擇最后一行，但是經過大量搜索之后，我仍然似乎找不到答案（我想我需要將數據存儲在數組中，然后調用該變量將數據導出為ex​​cel文件的代碼中的數組）。 所有幫助將不勝感激。 我的代碼（縮減版本）為：

<?php
    // Apply server security settings and keep cookies
    // connecting to the server
    // selecting the appropriate database
    //storing and fetching user data

$generate_query = "SELECT * FROM main_report";

$generate_data = mysql_query($generate_query, $link);

while($report = mysql_fetch_array($generate_data))
            {   

            $reportnoout = "<td>".$report['report_number']."</td>";

            $incdateout = "<td>".$report['incident_time']."</td>";

            $siteout = "<td>".$site_data['site_name']."</td>";

            $deptout = "<td>".$dept_data['department_name']."</td>";

            $reportout = "  <td>".$report['report_type']."</td>";

            $superout = "<td>".$staff_data5['name']."</td>";

            $descout = "<td>".$report['detailed_desc']."</td>"; 

// Needs some form of array declaration here maybe? 

            }       
// filename for download
$filename = "test_data_" . date('Ymd') . ".xls";    
header("Content-type: application/vnd.ms-excel");
header("Content-Disposition: attachment; filename=$filename"); 
$test="<table><th>Report No.</th><th>Incident Date</th><th>Site</th><th>Department</th><th>Incident Type</th><th>Responsible Supervisor</th><th>Description</th><tr>";
$test2="$reportnoout $incdateout $siteout $deptout $reportout $superout $descout"; // This is not right either should probably be an array or not even here?
echo $test;
echo $test2; // This was a stop gap to at least see if some of the code worked
exit;
?>

提前謝謝了。

干杯

附言：我通過在最近幾天的網上搜索來整理這段代碼，並將其與之前的內容放在一起，我從未從事過此類工作（輸出文件類型）

Answer 1

您的代碼可能需要進行大量清理，但是稍后我將讓您弄清楚這一點，並集中精力使其按預期工作。

您可以使用串聯.=來完成此操作

//start table string
$table = "<table><tr>
        <th>Report No.</th>
        <th>Incident Date</th>
        <th>Site</th>
        <th>Department</th>
        <th>Incident Type</th>
        <th>Responsible Supervisor</th>
        <th>Description</th><tr>";

$generate_query = "SELECT * FROM main_report";  
$generate_data = mysql_query($generate_query, $link);    

while($report = mysql_fetch_array($generate_data))
{   
    //add row to string using concatenation
    $table .= "<tr><td>{$report['report_number']}</td>
               <td>{$report['incident_time']}</td>
               <td>{$site_data['site_name']}</td>
               <td>{$dept_data['department_name']}</td>
               <td>{$report['report_type']}</td>
               <td>{$staff_data5['name']}</td>
               <td>{$report['detailed_desc']}</td></tr>";
}       

//close table
$table .="</table>";

// filename for download
$filename = "test_data_" . date('Ymd') . ".xls";    
header("Content-type: application/vnd.ms-excel");
header("Content-Disposition: attachment; filename=$filename"); 

echo $table;