如何將AngularFire2身份驗證作為可觀察對象？

Question

我希望經過身份驗證的設置isAuthenticated：成功聯合Google登錄后boolean為True，或者用戶已登錄狀態。

import {Injectable} from '@angular/core';
import {AngularFire} from 'angularfire2';
import {Observable} from 'rxjs/Observable';


//this current code is not making sense. Any suggestion 
//to make it an Observable for Signin and Logout?
@Injectable()
export class AuthService {
  isAuthenticated:boolean = false;
  authObj: Observable<any>;

  constructor(public af:AngularFire) {
    this.authObj = af.auth;
  }

  signin() {
    //I want to make AngularFire2 Authentication token/obj an Observable. So this will keep emitting an Observable
    //that return True.... after successful Federated Google Signin. I want my other component to subscribe to this Observable.
    return this.authObj.do(val => this.af.auth.login());
    this.isAuthenticated = true;
  }

}

Answer 1

我寫了一篇文章，把一些零碎的東西連在一起。 您可能需要創建如下的Auth服務：

import 'rxjs/add/operator/map';
import 'rxjs/add/operator/first';
import { Observable } from 'rxjs/Observable';

import { Injectable } from '@angular/core';
import { CanActivate, Router, ActivatedRouteSnapshot, RouterStateSnapshot } from '@angular/router';
import { AngularFire } from 'angularfire2';

@Injectable()
export class AuthGuard implements CanActivate{
  public allowed: boolean;

  constructor(private af: AngularFire, private router: Router) { }

  canActivate(route: ActivatedRouteSnapshot, state: RouterStateSnapshot): Observable<boolean> {
    return this.af.auth.map((auth) =>  {
      if(auth == null) {
        this.router.navigate(['/login']);
        return false;
      } else {
        return true;
      }
    }).first()
  }
}

有關詳細信息，請查看AngularFire2身份驗證文章 。

Answer 2

只需訂閱auth對象，以便在有用戶對象時收到通知......

  var auth = this.af.auth.subscribe( (user) => {
    debugger;
    if (user) {
      // User signed in!
      var uid = user.uid;
      console.log(uid)
    } else {
      // User logged out
      console.log("no user")
    }
  });

Answer 3

使用Angular v6 ， Firebase v5.0.*和angularfire2 5 rc 10你可以做這樣的事情。

...
import { AngularFireAuth } from 'angularfire2/auth';
import { map } from 'rxjs/operators';

...
export class DashboardGuard implements CanActivate, CanActivateChild {

  constructor(private router: Router, private auth: AngularFireAuth) { }
  // #2
  canActivate(route: ActivatedRouteSnapshot, state: RouterStateSnapshot) {
    // #1
    return this.auth.authState.pipe(
      // #3
      map((user: any) => user !== null) // <--- [1]
    );

  }

  canActivateChild(route: ActivatedRouteSnapshot, state: RouterStateSnapshot) {
    return this.canActivate(route, state);
  }

}

直接使用AngularFireAuth的authState其向下管道並檢查用戶是否不等於null [1] 。

1. authState返回Observable<firebase.User> authState Observable<firebase.User>
2. canActivate()返回Observable<boolean> | Promise<boolean> | boolean Observable<boolean> | Promise<boolean> | boolean
3. 訂閱authState會發出null ，如果沒有認證else發出firebase.User （見下圖）。

我剛剛發現我現在可以使用最新版本執行此操作 - >在canActivate返回一個Observable<boolean> ...因為在最后的版本中雖然在文檔中說canActivate返回Observable<boolean>但它給了我噸錯誤。 但是現在好了！

順便說一句我只是想分享我在角度v6之前寫道路防護的方法。 使用承諾

constructor(private router: Router, private afAuth: AngularFireAuth) {}

canActivate(next: ActivatedRouteSnapshot, state: RouterStateSnapshot) {
  const promise = new Promise(
    (resolve, reject) => {
      this.afAuth.authState.subscribe((state: any) => {
        resolve(state !== null);
      });
    }
  );

  return promise.then((data: boolean) => {
    if (data) {
      return data;
    } else {
      this.router.navigate(['/']);
    }
  });
}