[英]PHP json_decode returns null from string
現在,我正在做一個應用程序,它將來自Google Maps的一系列坐標保存到隱藏的輸入中,然后從表單向PHP獲取數據,它的輸出正常,但是當我嘗試讀取字符串並解碼JSON時,它返回空值。
現在,這是我的Javascript代碼:
var bounds = [];
var bound = {};
polygon.getPaths().forEach(function(punto, indice){
punto.forEach(function(puntoX, indice){
bound = {'lat': puntoX.lat(), 'lng': puntoX.lng()};
bounds.push(bound);
});
});
$('#bounds').val(JSON.stringify(bounds));
HTML代碼:
<form class="signup-block" method="POST" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]) . "?c=create"; ?>">
<button id="save" class="button success disabled" type="submit" disabled>Crear Geocerca</button>
<br>
<h3>Datos de la geocerca</h3>
<label for="nombre">Nombre de la geocerca:</label>
<input type="text" id="nombre" name="nombre" required />
<label for="tipo">Tipo de geocerca:</label>
<input type="text" id="tipo" name="tipo" readonly />
<div id="registro"></div>
<input id="bounds" type="hidden" name="bounds" />
這是由JS賦值后的值的邊界輸入
<input id="bounds" type="hidden" name="bounds" value="[{"lat":-2.1585226452743442,"lng":-79.8945227265358},{"lat":-2.1670138304221926,"lng":-79.9018183350563},{"lat":-2.176963037271158,"lng":-79.8945227265358},{"lat":-2.1733607458083646,"lng":-79.875468313694},{"lat":-2.1587799546129793,"lng":-79.8783865571022}]">
PHP代碼:
$bounds =filter_input(INPUT_POST,"bounds", FILTER_SANITIZE_STRING);
if (!$bounds) {
$this->error['error'] = 'Parametros incorrecto';
}else{
$coords = json_decode($bounds);
echo var_dump($bounds);//Outputs something
echo var_dump($coords);//Outputs null
我已經檢查過了,並且$ bounds變量獲取了值,但是它無法將它們讀取為JSON,我在做什么錯呢?
這是兩個var_dumps的輸出$ bounds的輸出
string(408) "[{"lat":-2.1581795660883976,"lng":-79.90096002817154},{"lat":-2.171559596852916,"lng":-79.9018183350563},{"lat":-2.176448424731824,"lng":-79.89057451486588},{"lat":-2.1662419064644722,"lng":-79.88053232431412},{"lat":-2.156206859267206,"lng":-79.8930636048317},{"lat":-2.15835110569104,"lng":-79.90164667367935}]"
$ coords的輸出
NULL
如果其他任何人都和我一樣,則問題是HTML輸出將所有的“和”打印為html實體,因此首先需要這樣做
$bounds = html_entity_decode($bounds);
$coords = json_decode($bounds, true);
echo var_dump($coords);
我花了很長時間才以不同的方式分析頁面輸出
您可以嘗試以下方法:jsondecode($ bounds,true)
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