[英]Android Retrofit no response
我只是剛剛改裝服務的新手,並按照本教程https://www.simplifiedcoding.net/retrofit-android-tutorial-to-get-json-from-server/它運作良好,並希望創建我自己的我使用了一個新的json網站http://api.androidhive.info/contacts/
{
"contacts": [
{
"id": "c200",
"name": "Ravi Tamada",
"email": "ravi@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c201",
"name": "Johnny Depp",
"email": "johnny_depp@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c202",
"name": "Leonardo Dicaprio",
"email": "leonardo_dicaprio@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c203",
"name": "John Wayne",
"email": "john_wayne@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c204",
"name": "Angelina Jolie",
"email": "angelina_jolie@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "female",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c205",
"name": "Dido",
"email": "dido@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "female",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c206",
"name": "Adele",
"email": "adele@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "female",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c207",
"name": "Hugh Jackman",
"email": "hugh_jackman@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c208",
"name": "Will Smith",
"email": "will_smith@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c209",
"name": "Clint Eastwood",
"email": "clint_eastwood@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c2010",
"name": "Barack Obama",
"email": "barack_obama@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c2011",
"name": "Kate Winslet",
"email": "kate_winslet@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "female",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
},
{
"id": "c2012",
"name": "Eminem",
"email": "eminem@gmail.com",
"address": "xx-xx-xxxx,x - street, x - country",
"gender" : "male",
"phone": {
"mobile": "+91 0000000000",
"home": "00 000000",
"office": "00 000000"
}
}
]
我實現了自己的接口ContactAPI.java
public interface ContactsAPI {
@GET("/contacts/")
public void getContacts(Callback<List<Contact>> response);}
並實現了類似Contact.java的模型類
public class Contact {
@SerializedName("id")
@Expose
private String id;
@SerializedName("name")
@Expose
private String name;
@SerializedName("email")
@Expose
private String email;
@SerializedName("address")
@Expose
private String address;
@SerializedName("gender")
@Expose
private String gender;
public String getId() {return id;}
public void setId(String id) {this.id = id;}
public String getName() {return name;}
public void setName(String name) {this.name = name;}
public String getEmail() {return email;}
public void setEmail(String email) {this.email = email;}
public String getAddress() {return address;}
public void setAddress(String address) {this.address = address;}
public String getGender() {return gender;}
public void setGender(String gender) {this.gender = gender;}}
然后終於在MainActivity.class中實現了我的Restadapter
public static final String ROOT_URL = "http://api.androidhive.info";
private ListView listView;
private List<Contact> contacts;
RestAdapter adapter = new RestAdapter.Builder().setEndpoint(ROOT_URL).build();
ContactsAPI api = adapter.create(ContactsAPI.class);
api.getContacts(new Callback<List<Contact>>() {
@Override
public void success(List<Contact> list, Response response) {
Toast.makeText(MainActivity.this,list.toString(),Toast.LENGTH_SHORT).show();
showList();
}
@Override
public void failure(RetrofitError error) {
//you can handle the errors here
Toast.makeText(MainActivity.this,"Error Occured:"+error.toString(),Toast.LENGTH_SHORT).show();
}
});
該應用程序運行順利,但延遲4秒后,它將提出一個錯誤,即公共無效失敗(RetrofitError錯誤)我不知道我錯過了什么我檢查了我的代碼,找不到任何錯誤請幫助我提前感謝。
如果json是這樣你需要一個類:
public class Contacts {
@SerializedName("contacts")
@Expose
private List<Contact> contacts = new ArrayList<Contact>();
/**
*
* @return
* The contacts
*/
public List<Contact> getContacts() {
return contacts;
}
/**
*
* @param contacts
* The contacts
*/
public void setContacts(List<Contact> contacts) {
this.contacts = contacts;
}
}
也在你的界面ContactAPI.java中
public interface ContactsAPI {
@GET("/contacts/")
public void getContacts(Callback<Contacts> response);
}
另請檢查此鏈接,因為“+”存在問題,此錯誤
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