我想將表單中的數據插入表中，然后從另一個表中選擇另一個數據並使用PHP插入到第三張表中

Question

我有三個相關的表“用戶”，“類別”和“ interest_area”； 我想將表單中的數據插入“用戶”表中，並從“類別”表中選擇另一個數據，然后使用PHP插入“ interest_area”表中。

它顯示的錯誤是：

錯誤：INSERT INTO用戶（user_id，first_name，last_name，higher_education，user_name，pass_word）VALUES（''，'87878787'，'iuiu'，'iuiu'，'root'，''）; INSERT INTO interest_area（category_id）SELECT category_id從類別WHERE category_name ='ASP'; 在'INSERT INTO interest_area（category_id）中選擇類目ID從FROM類別'-la ligne 2

我的PHP代碼是：

<?php
   if (isset($_POST["interest_area"])){             
   $f_name = $_POST["firstname"];
   $l_name = $_POST["last_name"];
   $h_education = $_POST["higher_education"];
   $i_area = $_POST["interest_area"];
   $email = $_POST["email"];
   $u_name = $_POST["user_name"];
   $p_word = $_POST["pass_word"];

  $sql = "INSERT INTO users(user_id, first_name, last_name,   higher_education, user_name, pass_word)
  VALUES('' , '$f_name' , '$l_name' , '$h_education' , '$username' ,  '$password');";

  $sql .= "INSERT INTO interest_area (category_id)
    SELECT category_id FROM category
    WHERE category_name = '$i_area';";

if ($conn->query($sql) === TRUE) {
echo "New record created successfully";} 
else { echo "Error: " . $sql . "<br>" . $conn->error;} 
}
?>

Answer 1

您必須運行兩個mysqli_query進行插入

mysqli_query

插入數據時更好地使用prepare語句

准備陳述

$f_name = $_POST["firstname"];
$l_name = $_POST["last_name"];
$h_education = $_POST["higher_education"];
$i_area = $_POST["interest_area"];
$email = $_POST["email"];
$u_name = $_POST["user_name"];
$p_word = $_POST["pass_word"];
$user_id = $_POST["user_id"];

$user_id如果它是您的主鍵，則不能插入數據；

 $sql1 = "INSERT INTO users(user_id, first_name, last_name,   higher_education, user_name, pass_word)
      VALUES('$user_id' , '$f_name' , '$l_name' , '$h_education' , '$u_name' ,  '$p_word')";

 $sql2 = "INSERT INTO interest_area (category_id)
     SELECT category_id FROM category WHERE category_name = '$i_area'";

 mysqli_query($con,$sql1);
 mysqli_query($con,$sql2) 
 mysqli_close($con);

Answer 2

您只需要將兩個INSERT語句作為單獨的$conn->query調用運行，而不是將它們串聯為一個調用。

Answer 3

語法錯誤在這里：

$sql .= "INSERT INTO interest_area (category_id)
SELECT category_id FROM category
WHERE category_name = '$i_area';";

應該是卷曲的...

$sql .= "INSERT INTO interest_area (category_id)
SELECT category_id FROM category
WHERE category_name = {$i_area};";

以及如所述的兩個獨立的查詢...

Answer 4

您需要對多個查詢使用multi_query。

$sql = "INSERT INTO users(user_id, first_name, last_name, higher_education, user_name, pass_word)VALUES('' , '$f_name' , '$l_name' , '$h_education' , '$username' , '$password');";

$sql .= "INSERT INTO interest_area (category_id)
     SELECT category_id FROM category WHERE category_name = '$i_area'";

 mysqli_multi_query($con,$sql);
 mysqli_close($con);