如何在Array中找到多個元素 - Javascript，ES6

Question

碼：

let names= ["Style","List","Raw"];
let results= names.find(x=> x.includes("s");
console.log(results); // 

如何從數組名稱中獲取包含“s”的名稱，目前，我只得到一個元素，但我需要所有出現。

Answer 1

你必須在這種情況下使用filter ，

let names= ["Style","List","Raw"];
let results= names.filter(x => x.includes("s"));
console.log(results); //["List"]

如果您希望它不區分大小寫，請使用以下代碼，

let names= ["Style","List","Raw"];
let results= names.filter(x => x.toLowerCase().includes("s"));
console.log(results); //["Style", "List"]

為了使它處於敏感狀態，我們必須將字符串的字符全部設置為小寫。

Answer 2

使用過濾器而不是find。

let names= ["Style","List","Raw"];
let results= names.filter(x => x.includes("s"));
console.log(results);

Answer 3

但是你也可以使用forEach（）方法：

var names = ["Style","List","Raw"];
var results = [];
names.forEach(x => {if (x.includes("s") || x.includes("S")) results.push(x)});
console.log(results); // [ 'Style', 'List' ]

或者如果你喜歡：

names.forEach(x => {if (x.toLowerCase().includes("s")) results.push(x)});