C ++編譯錯誤； 流運算符重載

Question

我正在學習C ++流運算符重載。 無法在Visual Studio中進行編譯。

在istream&運算符部分，編譯器僅在ins之后突出顯示克拉，並說no operator >> matches these operands 。

有人可以快速運行它並告訴我怎么了嗎？

*****************

// CoutCinOverload.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include <iostream>
#include <fstream>
using namespace std;

class TestClass {

friend istream& operator >> (istream& ins, const TestClass& inObj);

friend ostream& operator << (ostream& outs, const TestClass& inObj);

public:
    TestClass();
    TestClass(int v1, int v2);
    void showData();
    void output(ostream& outs);
private:
    int variable1;
    int variable2;
};

int main()
{
    TestClass obj1(1, 3), obj2 ;
    cout << "Enter the two variables for obj2: " << endl;
    cin >> obj2;  // uses >> overload
    cout << "obj1 values:" << endl;
    obj1.showData();
    obj1.output(cout);
    cout << "obj1 from overloaded carats: " << obj1 << endl;
    cout << "obj2 values:" << endl;
    obj2.showData();
    obj2.output(cout);
    cout << "obj2 from overloaded carats: " << obj2 << endl;

    char hold;
    cin >> hold;
    return 0;
}

TestClass::TestClass() : variable1(0), variable2(0)
{
}

TestClass::TestClass(int v1, int v2)
{
    variable1 = v1;
    variable2 = v2;
}

void TestClass::showData()
{
    cout << "variable1 is " << variable1 << endl;
    cout << "variable2 is " << variable2 << endl;
}

istream& operator >> (istream& ins, const TestClass& inObj)
{
    ins >> inObj.variable1 >> inObj.variable2;
    return ins;
}

ostream& operator << (ostream& outs, const TestClass& inObj)
{
    outs << "var1=" << inObj.variable1 << " var2=" << inObj.variable2 << endl;
    return outs;
}

void TestClass::output(ostream& outs)
{
    outs << "var1 and var2 are " << variable1 << " " << variable2 << endl;
}

Answer 1

operator >>()應該將TestClass&而不是const TestClass&作為其第二個參數，因為從istream讀取數據時，您應該修改該參數。

Answer 2

您應該將inObj的參數類型inObj為引用非常量，因為應該在operator>>對其進行修改。 您不能在const對象上進行修改，因此不能在const對象（及其成員）上調用opeartor>> ，這就是編譯器抱怨的地方。

friend istream& operator >> (istream& ins, TestClass& inObj);

Answer 3

刪除限定符const

friend istream& operator >> (istream& ins, const TestClass& inObj);
                                           ^^^^^

您不能更改常量對象。