[英]Read a line from a file in python
我有一個名為mcelog.conf
文件,正在用我的代碼讀取此文件。 該文件的內容是
no-syslog = yes # (or no to disable)
logfile = /tmp/logfile
程序將讀取mcelog.conf
文件並檢查no-syslog
標記,如果no-syslog = yes
則程序必須檢查標記logfile
並讀取logfile
標記。 誰能讓我知道如何獲取/tmp/logfile
值
with open('/etc/mcelog/mcelog.conf', 'r+') as fp:
for line in fp:
if re.search("no-syslog =", line) and re.search("= no", line):
memoryErrors = readLogFile("/var/log/messages")
mcelogPathFound = true
break
elif re.search("no-syslog =", line) and re.search("= yes", line):
continue
elif re.search("logfile =", line):
memoryErrors = readLogFile(line) # Here I want to pass the value "/tmp/logfile" but currently "logfile = /tmp/logfile" is getting passed
mcelogPathFound = true
break
fp.close()
將代碼更改為:
with open('/etc/mcelog/mcelog.conf', 'r+') as fp:
for line in fp:
if re.search("no-syslog =", line) and re.search("= no", line):
memoryErrors = readLogFile("/var/log/messages")
mcelogPathFound = true
break
elif re.search("no-syslog =", line) and re.search("= yes", line):
continue
elif re.search("logfile =", line):
emoryErrors = readLogFile(line.split("=")[1].strip()) # Here I want to pass the value "/tmp/logfile" but currently "logfile = /tmp/logfile" is getting passed
mcelogPathFound = true
break
fp.close()
這是因為您只想讀取行的一部分而不是整個內容,所以我只用“ =”符號將其拆分,然后將其剝離以刪除任何空白
我喜歡configparser
模塊的建議,因此這里是一個示例(Python 3)
對於給定的輸入,它將輸出reading /var/log/messages
import configparser, itertools
config = configparser.ConfigParser()
filename = "/tmp/mcelog.conf"
def readLogFile(filename):
if filename:
print("reading", filename)
else:
raise ValueError("unable to read file")
section = 'global'
with open(filename) as fp:
config.read_file(itertools.chain(['[{}]'.format(section)], fp), source = filename)
no_syslog = config[section]['no-syslog']
if no_syslog == 'yes':
logfile = "/var/log/messages"
elif no_syslog == 'no':
logfile = config[section]['logfile']
if logfile:
mcelogPathFound = True
memoryErrors = readLogFile(logfile)
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