while循環不適用於多個變量php？

Question

我正在嘗試創建一個while循環，該循環從Mysql數據庫中檢索所有相關數據，但不適用於多個變量，我認為問題在於while循環，因為我已經回顯了sql語句並檢索了值正確的變量，代碼為：

$wherein = implode(',', $_SESSION['cart']);
$sql = "select ID, Name, Price from lamps WHERE ID = '$wherein'";
$result = mysqli_query($conn, $sql);

echo "<table style='width:100%' border='1' >";
echo "<tr>";
echo "<th> Product Name</th>";
echo "<th>Product Price </th>" ;
echo "<th>Quantity </th>" ;
echo "</tr>";

while ( $row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
    echo "<tr>";
    echo "<td>" . $row['Name'] . "</td>";
    echo "<td> $". $row['Price'] . "</td>" ;
    echo "<td> <select>
        <option value= '1'>1</option> 
        <option value= '2'>2</option> 
        <option value= '3'>3</option> 
    </select>
    </td>";

    echo "</tr>";
}

echo "</table>";

我已經用代碼嘗試了很多事情，但是問題仍然存在，非常感謝您的幫助，謝謝。

Answer 1

</table>語句在while循環中。 因此，在第一個循環后關閉表后，其余數據可能不會在瀏覽器上顯示（它仍將出現在html源代碼中）。 通過將</table>語句移到最后一行來進行嘗試。

Answer 2

假設通過內插變量將具有多個ID，則應在sql中使用IN語句。

$wherein = implode("','", $_SESSION['cart']);
$sql = "select ID, Name, Price from lamps WHERE ID IN ( '$wherein' )";

渲染的輸出可以略微簡化，循環后應該關閉表！ 不知道$wherein wherein的內容很難回答，但我認為IN語句似乎比直接等於=更適合用於查詢的逗號分隔值的性質=

$wherein = implode("','", $_SESSION['cart']);
$sql = "select ID, Name, Price from lamps WHERE ID IN ( '$wherein' )";
$result= mysqli_query( $conn, $sql );

echo "
    <table style='width:100%' border='1' >
        <tr>
            <th> Product Name</th>
            <th>Product Price </th>
            <th>Quantity </th>
        </tr>";

while ( $row = mysqli_fetch_object( $result ) ){
    echo "
        <tr>
            <td>{$row->Name}</td>
            <td>${$row->Price}</td>
            <td>
                <select>
                    <option value= '1'>1
                    <option value= '2'>2
                    <option value= '3'>3
                </select>           
            </td>
        </tr>";
}
echo "
    </table>";


/* Example of using an array of IDs and imploding to generate where conditions for IN clause */

$cart=array('BGL1','BJL');
/* session - cart */

$wherein=implode( "','", $cart );
/* correctly add quotes around each string */

$sql="select ID, Name, Price from lamps WHERE ID IN ('$wherein');";
/* use the new $wherein string within quotes */
echo $sql;

>> select ID, Name, Price from lamps WHERE ID IN ('BGL1','BJL');