文件上傳無效| 腓
[英]File upload not working | Php
問題描述
我正在嘗試上傳php中的文件而無法執行此操作。 我正在嘗試上傳的文件是一個csv文件，但它不應該是一個問題。 我正在使用php上傳我的文件。 我也試圖在同一頁面處理表單。 下面是我的文件上傳代碼，它無法正常工作......
<!DOCTYPE html>
<html>
<head>
<title>File Upload</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
<input type="file" name="csv_file">
<input type="submit" name="submit">
</form>
<?php
if(isset($_POST['submit'])) {
if(isset($_POST['csv_file'])) {
echo "<p>".$_POST['csv_file']." => file input successfull</p>";
fileUpload();
}
}
function fileUpload () {
$target_dir = "var/import/";
$file_name = $_FILES['csv_file']['name'];
$file_tmp = $_FILES['csv_file']['tmp_name'];
if (move_uploaded_file($file_tmp, $target_dir.$file_name)) {
echo "<h1>File Upload Success</h1>";
}
else {
echo "<h1>File Upload not successfull</h1>";
}
}
?>
7 個解決方案
解決方案1
3 2016-08-22 06:41:09
使用enctype =“multipart / form-data”
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST" enctype="multipart/form-data">
<input type="file" name="csv_file">
<input type="submit" name="submit">
</form>
解決方案2
3 2016-08-22 06:41:48
使用enctype屬性更新您的表單代碼
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST" enctype = "multipart/form-data">
<input type="file" name="csv_file">
<input type="submit" name="submit">
</form>
解決方案3
2 已采納 2016-08-22 06:50:58
我嘗試下面的代碼，它的工作完美。
<!DOCTYPE html>
<html>
<head>
<title>File Upload</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST" enctype="multipart/form-data">
<input type="file" name="csv_file">
<input type="submit" name="submit">
</form>
<?php
if (isset($_POST['submit'])) {
echo "<p>" . $_POST['csv_file'] . " => file input successfull</p>";
$target_dir = "images ";
$file_name = $_FILES['csv_file']['name'];
$file_tmp = $_FILES['csv_file']['tmp_name'];
if (move_uploaded_file($file_tmp, $target_dir . $file_name)) {
echo "<h1>File Upload Success</h1>";
} else {
echo "<h1>File Upload not successfull</h1>";
}
}
?>
</body>
</html>
解決方案4
1 2016-08-22 06:43:16
用PHP上傳代碼[不檢查其擴展名]
<?php
if(isset($_POST['save'])){
$path="var/import/";
$name = $_FILES['csv_file']['name'];//Name of the File
$temp = $_FILES['csv_file']['tmp_name'];
if(move_uploaded_file($temp, $path . $name)){
echo "success";
}else{
echo "failed";
}
}
?>
<form method="post" action="" enctype="multipart/form-data">
<input type="file" name="csv_file">
<input type="submit" name="save" value="submit">
</form>
解決方案5
1 2016-08-22 06:56:16
它應該是這樣的
<!DOCTYPE html>
<html>
<head>
<title>File Upload</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST" enctype="multipart/form-data">
<input type="file" name="csv_file">
<input type="submit" name="submit">
</form>
<?php
if(isset($_POST['submit'])) {
if ($_FILES['csv_file']['size'] > 0)
{
echo "<p>".$_FILES['csv_file']['name']." => file input successfull</p>";
fileUpload();
}
}
function fileUpload () {
$target_dir = "var/import/";
$file_name = $_FILES['csv_file']['name'];
$file_tmp = $_FILES['csv_file']['tmp_name'];
if (move_uploaded_file($file_tmp, $target_dir.$file_name)) {
echo "<h1>File Upload Success</h1>";
}
else {
echo "<h1>File Upload not successfull</h1>";
}
}
?>
</body>
以下是您需要進行的更改
- 在表單標記中添加
enctype = "multipart/form-data"作為新屬性 - 從這個改變
if(isset($_POST['csv_file'])) {到這個if($_FILES['csv_file']['size'] > 0) {因為你需要檢查大小是否上傳 - 更改此
echo "<p>".$_POST['csv_file']." => file input successfull</p>";回到echo "<p>".$_FILES['csv_file']['name']." => file input successfull</p>";因為你需要使用$_FILES來獲取文件名而不是$_POST - 最后但並非最不重要的，完整的
</body>標簽，如果你還沒有。
解決方案6
1 2016-08-22 07:54:44
First Give permission to folder where you going to upload Ex: "var/import/" folder.
<!DOCTYPE html>
<html>
<head>
<title>File Upload</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST" enctype= "multipart/form-data">
<input type="file" name="csv_file">
<input type="submit" name="submit">
</form>
<?php
if(isset($_POST['submit'])) {
if(isset($_FILES['csv_file']) && $_FILES['csv_file']['size'] > 0) {
echo "<p>".$_FILES['csv_file']['name']." => file input successfull</p>";
fileUpload();
}
}
function fileUpload () {
$target_dir = "var/import/";
$file_name = $_FILES['csv_file']['name'];
$file_tmp = $_FILES['csv_file']['tmp_name'];
if (move_uploaded_file($file_tmp, $target_dir.$file_name)) {
echo "<h1>File Upload Success</h1>";
}
else {
echo "<h1>File Upload not successfull</h1>";
}
}
解決方案7
0 2018-07-14 10:56:49
對於上傳文件，技巧是enctype =“multipart / form-data”使用此表單定義
PHP文件上傳不起作用
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