[英]Laravel trying to get user id to store into posts table
public function store(Request $request)
{
$this->validate($request, array(
'title' => 'required|max:255|min:2',
'slug' => 'required|alpha_dash|unique:articles,slug',
'category_id' => 'required|integer',
'content' => 'required|min:2'
));
$article = new Article;
$article->title = $request->title;
$article->slug = $request->slug;
$article->category_id = $request->category_id;
$article->content = $request->content;
$article->save();
Session::flash('success', 'Your article has been published.');
return redirect()->route('article.show', $article->id);
}
文章表上有一個user_id列,
這是我的存儲功能,但是當我創建帖子時,我正在尋找一種將登錄的用戶ID存儲到articles表中的user_id列的方法。
獲取auth
用戶。
$article->user_id = Auth::user()->id;
$article->save();
簡單
$article->user_id = Auth::user()->id;
它將已認證的用戶ID存儲在商品表的user_id
字段中。
根據您的情況,將您的商店代碼更改為
public function store(Request $request)
{
$this->validate($request, array(
'title' => 'required|max:255|min:2',
'slug' => 'required|alpha_dash|unique:articles,slug',
'category_id' => 'required|integer',
'content' => 'required|min:2'
));
$article = new Article;
$article->title = $request->title;
$article->slug = $request->slug;
$article->category_id = $request->category_id;
//it will store the current logged in user id in user_id field
$article->user_id = Auth::user()->id;
$article->content = $request->content;
$article->save();
Session::flash('success', 'Your article has been published.');
return redirect()->route('article.show', $article->id);
}
但是還有另一種方法,甚至不使用名稱空間和全部。
您可以使用以下代碼解決此問題:
$article->user_id = auth()->user()->id;
代替:
$article->user_id = Auth::user()->id;
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