如何使用正則表達式將一個字符串替換為另一個字符串？

Question

從文件輸入文本：

someother block {
  enable route yes;
  dhcp auto;
  ....
}
options { 
  dnssec-enable yes;
  dnssec-validation yes;
  dnssec-lookaside auto;
 .....
}

我想，以取代所有的“是”和“自動”文字選項分別阻止只能用“沒有”和“手動”。

我該怎么做？

這是我的執行情況，但文字沒有被替換。

String dataPattern  = "\noptions \\{\\s*\n(dnssec-[a-z]+ ([a-z]+));";
Pattern filePattern = Pattern.compile(dataPattern, Pattern.DOTALL);
Matcher filePatternMatcher = filePattern.matcher(input);
if(filePatternMatcher.find()){
        System.out.println("0 - "+filePatternMatcher.group(0)); //0 - \ndnssec-enable yes;
        System.out.println("1 - "+filePatternMatcher.group(1)); //1 - dnssec-enable yes

        System.out.println("2 - "+filePatternMatcher.group(2)); //2 - yes
        String value = filePatternMatcher.group(2);
        value.replaceAll("\ndnssec-enable ([a-z]+);", "$1somethingelse");
        System.out.println("new replaced text:"+value); \\ new-replaced text: yes
}

Answer 1

我認為您只需使用替換功能就可以完成它！

    String test="someother block {" +
            "  enable route yes;" +
            "  dhcp auto;" +
            "  ...." +
            "}" +
            "options { " +
            "  dnssec-enable yes;" +
            "  dnssec-validation yes;" +
            "  dnssec-lookaside auto;" +
            " ....." +
            "}";

    String result;

    int opStartIndex=test.indexOf("options");
    int opEndIndex=opStartIndex+ test.substring(opStartIndex).indexOf("}");
    result=test.substring(0,opStartIndex)+test.substring(opStartIndex, opEndIndex).replace("yes","no").replace("auto","manual")+test.substring(opEndIndex);
    System.out.println(result);