具有主義實體的Symfony表單-無法加載關系進行編輯

Question

我對某些我認為可能很基本的東西有疑問，但原因正在逃避。

我有兩個實體，一個組織和一個訂閱。 一個組織與一個訂閱鏈接。

我希望能夠通過表單進行編輯（通過表單創建已經可以）。 當我執行以下操作時：

    $organisation = $this->getDoctrine()->getRepository('AppBundle\Entity\Organisation')
        ->findOneBy(array(
            'id' => $id
        ));

    $form = $this->createForm(new OrganisationType(), $organisation, array(
        'method' => 'POST'
    ));

    $form->submit($paramFetcher->all());

我收到一個異常，因為未設置組織實體的預訂屬性（盡管將具有預訂的屬性傳遞給默認表單）。 異常如下：

Expected argument of type "AppBundle\Entity\Subscription", "NULL" given

很明顯，這是由Organization實體上的setSubscription方法拋出的，但是我不確定為什么該表單應該將轉換為Int值的int值自動轉換為Subscription實體。

我在這里做蠢事嗎？ 我已在下面附上了相關代碼。 謝謝！

復制此問題的最簡單的控制器操作

public function testAction(Request $request)
{

    $organisation = $this->getDoctrine()->getRepository('AppBundle\Entity\Organisation')
        ->findOneBy(array('id' => 7));

    $form = $this->createForm(new OrganisationType(), $organisation);

    $form->submit($request->request->all());

    return $this->render('test.html.twig', array(
        'testform' => $form->createView()
    ));

}

Organisation.php

<?php

namespace AppBundle\Entity;

use Doctrine\Common\Collections\Collection;
use Doctrine\ORM\Mapping as ORM;
use JMS\Serializer\Annotation as JMS;
use Gedmo\Mapping\Annotation as Gedmo;
use Symfony\Component\Validator\Constraints as Assert;

/**
 * Organisation
 *
 * @ORM\Table(name="organisation")
 * @ORM\Entity(repositoryClass="AppBundle\Repository\OrganisationRepository")
 */
class Organisation
{

const ENABLED = 1;
const DISABLED = 2;

/**
 * @var int
 *
 * @ORM\Column(name="id", type="integer")
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="AUTO")
 * @JMS\Groups({"default", "list-organisation"})
 */
private $id;

/**
 * @var string
 *
 * @ORM\Column(name="name", type="string", length=255)
 * @JMS\Groups({"default", "list-organisation"})
 */
private $name;

/**
 * @var Subscription|null The subscription this organisation is currently linked to
 * @ORM\ManyToOne(targetEntity="Subscription", inversedBy="organisations")
 * @ORM\JoinColumn(name="subscription_id", referencedColumnName="id", onDelete="set null")
 * @JMS\Groups({"default", "list-organisation"})
 */
private $subscription;

/**
 * @var Collection
 * @ORM\OneToMany(targetEntity="User", mappedBy="organisation")
 * @JMS\Groups({})
 */
private $users;

/**
 * @var Collection
 * @ORM\OneToMany(targetEntity="Subgroup", mappedBy="organisation")
 * @JMS\Groups({"default"})
 */
private $subgroups;

/**
 * @var string $enabled
 *
 * @ORM\Column(type="string")
 */
private $enabled = self::ENABLED;

/**
 * @var datetime $created
 *
 * @Gedmo\Timestampable(on="create")
 * @ORM\Column(type="datetime")
 * @JMS\Groups({"default", "list-organisation"})
 */
private $created;

/**
 * @var datetime $updated
 *
 * @Gedmo\Timestampable(on="update")
 * @ORM\Column(type="datetime")
 * @JMS\Groups({"default", "list-organisation"})
 */
private $updated;

/**
 * Get id
 *
 * @return integer 
 */
public function getId()
{
    return $this->id;
}

/**
 * Set name
 *
 * @param string $name
 * @return Organisation
 */
public function setName($name)
{
    $this->name = $name;

    return $this;
}

/**
 * Sets subscription
 *
 * @param Subscription $subscription
 * @return $this
 */
public function setSubscription(Subscription $subscription)
{
    $this->subscription = $subscription;

    return $this;
}

/**
 * Gets subscription
 *
 * @return Subscription|null
 */
public function getSubscription()
{
    return $this->subscription;
}

/**
 * Sets enabled
 *
 * @param $enabled
 */
public function setEnabled($enabled)
{
    if (!in_array($enabled, array(self::ENABLED, self::DISABLED))) {
        throw new \InvalidArgumentException('Invalid enabled status');
    }

    $this->enabled = $enabled;
}

/**
 * Gets enabled
 *
 * @return string
 */
public function getEnabled()
{
    return $this->enabled;
}

/**
 * Get name
 *
 * @return string 
 */
public function getName()
{
    return $this->name;
}

/**
 * Returns Users belonging to this organisation
 *
 * @return Collection
 */
public function getUsers()
{
    return $this->users;
}

public function __toString()
{
    return $this->getName();
}
}

Subscription.php

<?php

namespace AppBundle\Entity;

use Doctrine\Common\Collections\Collection;
use Doctrine\ORM\Mapping as ORM;
use JMS\Serializer\Annotation as JMS;
use Gedmo\Mapping\Annotation as Gedmo;

/**
 * Organisation
 *
 * @ORM\Table(name="subscription")
 * @ORM\Entity(repositoryClass="AppBundle\Repository\SubscriptionRepository")
 */
class Subscription
{
/**
 * @var int
 *
 * @ORM\Column(name="id", type="integer")
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="AUTO")
 * @JMS\Groups({"default", "list-organisation"})
 */
private $id;

/**
 * @var string
 *
 * @ORM\Column(name="name", type="string", length=255)
 * @JMS\Groups({"default", "list-organisation"})
 */
private $name;

/**
 * @var Collection
 * @ORM\OneToMany(targetEntity="Organisation", mappedBy="subscription")
 * @JMS\Groups({"default"})
 */
private $organisations;

/**
 * @var datetime $created
 *
 * @Gedmo\Timestampable(on="create")
 * @ORM\Column(type="datetime")
 * @JMS\Groups({"default"})
 */
private $created;

/**
 * @var datetime $updated
 *
 * @Gedmo\Timestampable(on="update")
 * @ORM\Column(type="datetime")
 * @JMS\Groups({"default"})
 */
private $updated;

/**
 * Get id
 *
 * @return integer 
 */
public function getId()
{
    return $this->id;
}

/**
 * Set name
 *
 * @param string $name
 * @return Subscription
 */
public function setName($name)
{
    $this->name = $name;

    return $this;
}

/**
 * Get name
 *
 * @return string 
 */
public function getName()
{
    return $this->name;
}

/**
 * Returns Organisations with this subscription type
 *
 * @return Collection
 */
public function getOrganisations()
{
    return $this->organisations;
}

/**
 * @return string
 */
public function __toString()
{
    return $this->getName();
}
}

OrganisationType.php

<?php

namespace AppBundle\Form;

use Doctrine\Common\Persistence\ObjectManager;
use Symfony\Bridge\Doctrine\Form\Type\EntityType;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;

class OrganisationType extends AbstractType
{
private $manager;

public function __construct(ObjectManager $objectManager)
{
    $this->manager = $objectManager;
}

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder->add('name');
    $builder->add('subscription', EntityType::class, array(
        'class' => 'AppBundle\Entity\Subscription'
    ));

}

public function configureOptions(OptionsResolver $resolver)
{
    $resolver->setDefaults(array(
        'data_class' => 'AppBundle\Entity\Organisation',
        'csrf_protection' => false
    ));
}
}

Answer 1

在新的Symfony 3.1上，這就像一種魅力（如先前的評論所述，這是處理表單提交的推薦方法）：

public function testAction(Request $request)
{
    $organisation = $this->getDoctrine()->getRepository('AppBundle\Entity\Organisation')
        ->find(1);

    $form = $this->createForm(OrganisationType::class, $organisation);

    $form->handleRequest($request);

    if ($form->isSubmitted() && $form->isValid()) {
        $this->getDoctrine()->getManager()->persist($organisation);
        $this->getDoctrine()->getManager()->flush();

        die('saved into database.');
    }

    return $this->render('test.html.twig', array(
        'testform' => $form->createView()
    ));

}