[英]How to write data into multiple HTML table columns with PHP?
我使這段代碼將數據寫入HTML表:
<?php
//DB Verbindung
$con = mysqli_connect("localhost","root","","altislife");
$header = -1;
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql="SELECT * FROM players";
if ($result=mysqli_query($con,$sql))
{
echo "<thead><tr>";
while ($fieldinfo=mysqli_fetch_field($result))
{
echo "<th>$fieldinfo->name</th>";
$header++;
echo "$header";
}
echo "</tr></thead>";
mysqli_free_result($result);
}
if ($result=mysqli_query($con,$sql))
{
echo "<tbody>";
for ($i=0; $i < $header; $i++) {
while($sql = mysqli_fetch_array($result))
{
echo "<tr><td>" . $sql[$i] . "</td><td> ";
}
}
echo "</tbody>";
}
mysqli_close($con);
問題在於它僅填充第一列。
然后我嘗試了這個:
<?php
//DB Verbindung
$con = mysqli_connect("localhost","root","","altislife");
$header = -1;
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql="SELECT * FROM players";
if ($result=mysqli_query($con,$sql))
{
echo "<thead><tr>";
while ($fieldinfo=mysqli_fetch_field($result))
{
echo "<th>$fieldinfo->name</th>";
$header++;
echo "$header";
}
echo "</tr></thead>";
mysqli_free_result($result);
}
if ($result=mysqli_query($con,$sql))
{
echo "<tbody>";
while($sql = mysqli_fetch_array($result))
{
for ($i=0; $i < $header; $i++) {
echo "<tr><td>" . $sql[$i] . "</td><td> ";
}
}
echo "</tbody>";
}
mysqli_close($con);
此代碼的問題與第一個示例相同。 誰能看到我的錯誤?
if ($result=mysqli_query($con,$sql))
{
$row = mysqli_fetch_assoc($result);
$html = '<table><tr><th>'.implode('</th><th>',array_keys($row)).'</th></tr>';
do {
$html .= '<tr><td>'.implode('</td><td>',$row).'</td></tr>';
}while($row = mysqli_fetch_assoc($result));
$html .='</table>';
}
echo $html;
這樣嘗試,並弄清楚它是如何工作的;-)
指向您的代碼:
tbody
不是table
您的第一個示例沒有表格標簽 <tr></tr>
你的第二個例子錯過了結束標記 thead
和tbody
是可選的,對html沒有影響 最后一點:不必運行sql兩次以生成表
implode($sep,$arr)
implode像<th></th>
一樣接受了args和分隔符,並將數組的所有條目合並為: array('a','b','c')
變成a<th></th>b<th></th>c
mysqli_fetch_assoc
與mysqli_fetch_array
秒給出類似[0=>'a',1=>'b']
和第一個['name'=>'a','color'=>'b']
您需要獲取數據庫中的整個記錄,而不僅僅是一個字段。 嘗試fetch_assoc(請參閱http://www.w3schools.com/php/php_mysql_select.asp )。
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "id: " . $row["id"]. " - Name: " . $row["firstname"]. " " . $row["lastname"]. "<br>";
}
} else {
echo "0 results";
}
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