[英]Haskell Recursive Type Classes
我想創建一個基於元組的遞歸實例類型。 我正在尋找的是與此類似的東西:
class Provider a b where
getInstance :: a -> b
instance Provider a b => Provider (x, a) b where
getInstance (x, a) = getInstance a
instance Provider (b, x) b where
getInstance (b, _) = b
tryFunc1 :: Int
tryFunc1 =
let provider = ("test", (10, ())) :: (String, (Int, ()))
in getInstance provider
tryFunc2 :: String
tryFunc2 =
let provider = ("test", (10, ())) :: (String, (Int, ()))
in getInstance provider
不幸的是,haskell 無法解決該實例。 任何原因?
解決方案是停止使用已棄用的OverlappingInstances
編譯指示,並開始使用每個實例的OVERLAPPING
和OVERLAPPABLE
編譯指示。 僅此更改:
instance {-# OVERLAPPABLE #-} Provider a b => Provider (x, a) b where
getInstance (x, a) = getInstance a
instance {-# OVERLAPPING #-} Provider (b, x) b where
getInstance (b, _) = b
我得到tryFunc1
是10
和tryFunc2
是"test"
。
從技術上講,您只需要OVERLAPPABLE
或OVERLAPPING
編譯指示,但我相信在這種情況下同時擁有兩者是一種很好的做法……另外,我想這是您想要的行為,但請注意,這只是獲得第一個您正在尋找的類型(所以getInstance (10, (20, ())) :: Int
給我10
而不是20
)
信息的良好來源是門票跟蹤功能的創作。
我知道有些人不喜歡UndecidableInstances
但這就是我在這種情況下喜歡做的:使用封閉的type family
來明確選擇是完全確定的。
這個想法是讓類型族計算一個布爾標志,明確類型類解析機制應該采用哪個分支。 由於Provider ab (AtHead ab) =>
約束,即使它是無害的,也需要UndecidableInstance
擴展。
{-# LANGUAGE MultiParamTypeClasses #-}
{-# LANGUAGE FlexibleInstances #-}
{-# LANGUAGE FlexibleContexts #-}
{-# LANGUAGE UndecidableInstances #-}
{-# LANGUAGE TypeFamilies #-}
{-# LANGUAGE DataKinds #-}
{-# LANGUAGE TypeOperators #-}
{-# LANGUAGE ScopedTypeVariables #-}
module Provider where
import Data.Proxy
import Data.Type.Equality
class Provider a b (f :: Bool) where
getInstance' :: Proxy f -> a -> b
type family AtHead x y :: Bool where
AtHead (x, a) y = x == y
instance Provider a b (AtHead a b) => Provider (x, a) b 'False where
getInstance' _ (x, a) = getInstance' (Proxy :: Proxy (AtHead a b)) a
instance Provider (b, x) b 'True where
getInstance' _ (b, _) = b
getInstance :: forall a b. Provider a b (AtHead a b) => a -> b
getInstance = getInstance' (Proxy :: Proxy (AtHead a b))
tryFunc1 :: Int
tryFunc1 =
let provider = ("test", (10, ())) :: (String, (Int, ()))
in getInstance provider
tryFunc2 :: String
tryFunc2 =
let provider = ("test", (10, ())) :: (String, (Int, ()))
in getInstance provider
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