Swift 將 JSON 解析為數組

Question

我一直在使用 swift 應用程序。 我堅持將多個數據解析為數組，這是我的 json

    {
"error":0,
"success":1,
"kode_keranjang":"2",
"kode_produk":"1",
"kode_pelanggan":"USR-6cs42",
"jumlah":"1",
"nama_produk":"MacBook 2015",
"gambar":"MacBook.jpg",
"harga":"2000000",
"message":"Berhasil"
}
{
"error":0,
"success":1,
"kode_keranjang":"3",
"kode_produk":"2",
"kode_pelanggan":"USR-6cs42",
"jumlah":"1",
"nama_produk":"iPhone 6s",
"gambar":"iPhone",
"harga":"12000000",
"message":"Berhasil"
}

我怎樣才能快速獲得 nama_produk 作為數組？ 所以我可以在我的 tableview 單元格中填充它

這是我的 swift

        let myUrl = NSURL(string: "http://xxxxxxxx.com/produk.php");

    let request = NSMutableURLRequest(URL:myUrl!);

    request.HTTPMethod = "POST";// Compose a query string

    let postString = "produkid="+produkid!+"&kat="+kat!+"";

    request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding);

    let task = NSURLSession.sharedSession().dataTaskWithRequest(request) {
        data, response, error in

        if error != nil
        {
            print("error=\(error)")
            return
        }

        // You can print out response object
        print("response = \(response)")

        // Print out response body
        let responseString = NSString(data: data!, encoding: NSUTF8StringEncoding)
        print("responseString = \(responseString)")

        //Let's convert response sent from a server side script to a NSDictionary object:
        do {
            let myJSON =  try NSJSONSerialization.JSONObjectWithData(data!, options: .MutableContainers) as? NSDictionary

            if let parseJSON = myJSON {

                // Now we can access value of First Name by its key
                let nama_produk = parseJSON["nama_produk"] as? NSArray
                let status = parseJSON["success"] as? Int
                if(status == 1){


                    print (nama_produk);
                }
                else{
                   // let statusnya = "error";
                    return;
                }

            }
        } catch {
            print(error)
        }
    }
    task.resume()

在這一行

let nama_produk = parseJSON["nama_produk"] as? NSArray


print (nama_produk);

我將 nama_produk 創建為數組，然后嘗試打印它，但它是空的，不顯示數據。

然后我想像這樣在我的單元格中添加 nama_produk 數組

var nama_produk_array = [""+nama_produk+""]
cell.namaproduk.text = nama_produk_array[indexPath.row]

我如何將 json 解析為數組？

請某人

Answer 1

據我所知，您有一個字典數組，並希望將nama_produk字段提取到該數組中。 這是在Swift 3, Xcode 8 中執行此操作的安全方法：

var jsonString1 =
"{\"error\":0,\"success\":1,\"kode_keranjang\":\"2\",\"kode_produk\":\"1\",\"kode_pelanggan\":\"USR-6cs42\",\"jumlah\":\"1\",\"nama_produk\":\"MacBook 2015\",\"gambar\":\"MacBook.jpg\",\"harga\":\"2000000\",\"message\":\"Berhasil\"}"
var jsonString2 =
"{\"error\":0,\"success\":1,\"kode_keranjang\":\"3\",\"kode_produk\":\"2\",\"kode_pelanggan\":\"USR-6cs42\",\"jumlah\":\"1\",\"nama_produk\":\"iPhone 6s\",\"gambar\":\"iPhone\",\"harga\":\"12000000\",\"message\":\"Berhasil\"}"
var jsonString = "[" + jsonString1 + "," + jsonString2 + "]"

var data = jsonString.data(using: .utf8)!
do {
    if let json = try JSONSerialization.jsonObject(with: data, options : .allowFragments) as? [Dictionary<String,Any>]
    {
        let array = json
           .filter{ $0["success"] as? Int == 1}
           .flatMap{$0["nama_produk"] as? String}
        print(array) // ==> ["MacBook 2015", "iPhone 6s"]
    } else {
        print("bad json")
    }
} catch let error as NSError {
    print(error)
}

jsonString是可能的 json => 2 個字典jsonString1和jsonString2的數組

flatMap負責處理$0["nama_produk"]到String的失敗轉換，這可能會不必要地隱藏您收到的 json 問題，因此您可以考慮使用.map{ $0["nama_produk"] as! String } .map{ $0["nama_produk"] as! String }正如亞歷山大建議的那樣

Answer 2

您提供的不是有效的 JSON。 您必須有一個單一的頂級元素。 也許你想把它放在一個數組中，像這樣：

[
    {
        "error": 0,
        "success": 1,
        "kode_keranjang": "2",
        "kode_produk": "1",
        "kode_pelanggan": "USR-6cs42",
        "jumlah": "1",
        "nama_produk": "MacBook 2015",
        "gambar": "MacBook.jpg",
        "harga": "2000000",
        "message": "Berhasil"
    } {
        "error": 0,
        "success": 1,
        "kode_keranjang": "3",
        "kode_produk": "2",
        "kode_pelanggan": "USR-6cs42",
        "jumlah": "1",
        "nama_produk": "iPhone 6s",
        "gambar": "iPhone",
        "harga": "12000000",
        "message": "Berhasil"
    }
]

這是我對serg_zhd的回答的改進：

import Foundation

var jsonFragment1 =
"{\"error\":0,\"success\":1,\"kode_keranjang\":\"2\",\"kode_produk\":\"1\",\"kode_pelanggan\":\"USR-6cs42\",\"jumlah\":\"1\",\"nama_produk\":\"MacBook 2015\",\"gambar\":\"MacBook.jpg\",\"harga\":\"2000000\",\"message\":\"Berhasil\"}"
var jsonFragment2 =
"{\"error\":0,\"success\":1,\"kode_keranjang\":\"3\",\"kode_produk\":\"2\",\"kode_pelanggan\":\"USR-6cs42\",\"jumlah\":\"1\",\"nama_produk\":\"iPhone 6s\",\"gambar\":\"iPhone\",\"harga\":\"12000000\",\"message\":\"Berhasil\"}"
var jsonString = "[" + jsonFragment1 + "," + jsonFragment2 + "]"


func parse(JSON json: String) throws -> [String]? {
    guard let data = json.data(using: .utf8) else { return nil }

    guard let rootArray = try JSONSerialization.jsonObject(with: data, options : []) as? [[String: Any]]
    else { return nil }

    return rootArray
        .filter{ $0["success"] as? Int == 1}
        .map{ $0["nama_produk"] as! String }
}

if let devices = try parse(JSON: jsonString) {
    print(devices)
}
else {
    print("error parsing the json")
}

你可以在這里試試。

Answer 3

struct Product: Decodable {
    let namaProduk: String?
}

let JSON: String = """
[{
    "error": 0,
    "success": 1,
    "kode_keranjang": "2",
    "kode_produk": "1",
    "kode_pelanggan": "USR-6cs42",
    "jumlah": "1",
    "nama_produk": "MacBook 2015",
    "gambar": "MacBook.jpg",
    "harga": "2000000",
    "message": "Berhasil"
},
{
    "error": 0,
    "success": 1,
    "kode_keranjang": "3",
    "kode_produk": "2",
    "kode_pelanggan": "USR-6cs42",
    "jumlah": "1",
    "nama_produk": "iPhone 6s",
    "gambar": "iPhone",
    "harga": "12000000",
    "message": "Berhasil"
}]
"""

if let jsonData = JSON.data(using: .utf8) {

    let decoder = JSONDecoder()
    decoder.keyDecodingStrategy = .convertFromSnakeCase

    do {
        let products: [Product] = try decoder.decode([Product].self, from: jsonData)
        let namaProduks: [String] = products.compactMap { $0.namaProduk }
        print(namaProduks) // ["MacBook 2015", "iPhone 6s"]
    } catch {
        print(error) // handle the error
    }
}