在Playframework 2.4中找不到ebeans方法的“ byId（）”和“查找”

Question

我想在playframework 2.4中使用ebeans方法的'byId（）'；

程序返回“找不到符號byId（）”。

但是，“。all（）”方法可以工作並獲取數據。（我想知道為什么）。

這是代碼。

import java.util.List;
import models.UserMaster;
import com.avaje.ebean.Model.Finder;
import play.mvc.Controller;
import play.mvc.Result;
import views.html.*;
import com.avaje.ebean.Query;

public class TestController extends Controller {

public Result test(){

    //Finder<Long, UserMaster> finder = new Finder<Long,UserMaster> (Long.class, UserMaster.class);

    UserMaster UserMaster = UserMaster.find.byId(1L);

    return ok(test.render(teststring));

}
}

這是一個模型（摘要）。

package models;

import java.sql.Timestamp;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

import com.avaje.ebean.Model;
import com.avaje.ebean.annotation.CreatedTimestamp;
import com.avaje.ebean.annotation.UpdatedTimestamp;
import com.avaje.ebean.Model.Finder;


@Entity
@Table(name = "user_master")
public class UserMaster extends Model {

   @Id
   @Column(name = "user_id")
   private String userId;

   @Column(name = "user_name")
   private String userName;


   @Column(name = "password")
   private String password;

   @CreatedTimestamp
   @Column(name = "regist_time")
   private Timestamp registTime;


   @UpdatedTimestamp
   @Column(name = "update_time")
   private Timestamp updateTime;

/**
 * find
 */

public static Finder<Long, UserMaster> finder = new Finder<Long,UserMaster> (Long.class, UserMaster.class);


}

我也嘗試過finder.find.byid（1），但是它也沒有用。 請你幫我一下嗎？

Answer 1

您的模型：

import java.sql.Timestamp;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

import com.avaje.ebean.Model;
import com.avaje.ebean.annotation.CreatedTimestamp;
import com.avaje.ebean.annotation.UpdatedTimestamp;
import com.avaje.ebean.*;



@Entity
@Table(name = "user_master")
public class UserMaster extends Model {

   @Id
   @Column(name = "user_id")
   private String userId;

   @Column(name = "user_name")
   private String userName;


   @Column(name = "password")
   private String password;

   @CreatedTimestamp
   @Column(name = "regist_time")
   private Timestamp registTime;


   @UpdatedTimestamp
   @Column(name = "update_time")
   private Timestamp updateTime;

/**
 * find
 */

  public static Find<Long,UserMaster> find = new Find<Long,UserMaster>(){};


}

在您的控制器中：

public class TestController extends Controller {

  public Result test(){

    UserMaster UserMaster = UserMaster.find.byId(1L);

    return ok(test.render(teststring));

  }
}