[英]ajax js-php POST request not working, without jQuery
我找不到任何關於ajax的深入指南,特別是對於php服務器端。 我目前只嘗試將數據發布到PHP並測試它,然后嘗試轉儲到SQL。 工作了2天,仍然無法正常工作。 猜猜現在是進入股票溢出的好時機:html + js:
<script>//send data scripts var formNode = document.querySelector("#customerRegiForm"); var formData = new FormData(formNode); var request = new XMLHttpRequest(); request.open("POST", "php/formSubmission.php", true); request.onreadystatechange = function () { if(request.readyState == 4 && request.status == 200){ document.getElementById("testing").innerHTML = request.responseTexts; } }; request.send(formData); </script>
<form class="regiForm" id="customerRegiForm" onsubmit="return formValidation()"> <div> Name: <input type="text" id="firstName" name="firstname" class="" required /> Family Name: <input type="text" id="lastName" name="lastname" class="" required /> </div> <div> Email: <input type="email" class="" id="email" name="email "required /> </div> <div> Phone Number: <input type="text" id="phone" name="phone" class="" required /> </div> <div> Country: <select name="country" class="countries" id="countryId" style="width: 100px"> <option value="">Select Country</option> </select> State: <select name="state" class="states" id="stateId"> <option value="">Select State</option> </select> City: <select name="city" class="cities" id="cityId"> <option value="">Select City</option> </select> </div> <div> Address: <input type="text" name="address" /><br /> </div> <button type="submit">Submit</button> </form> <p id="testing"></p>
<?php
/**
* Created by PhpStorm.
* User: user
* Date: 17-Sep-16
* Time: 14:50
*/
echo $_POST['email'];
?>
此外,有關該主題的視頻和書籍的任何建議?
我不知道這是否只是你真實代碼的錯字,但是
request.responseTexts
應該
request.responseText
(最后的“s”不行)
您需要在代碼中更改一些內容,例如:
查看以下<input>
元素,
<input type="email" class="" id="email" name="email "required /> ^^^^^^^^^^^^^
email
后你能看到額外的空間嗎? 這就是為什么在PHP方面, echo $_POST['email'];
不行。 這個<input>
元素應該是這樣的:
<input type="email" class="" id="email" name="email" required />
在這里查看這個JavaScript語句,
document.getElementById("testing").innerHTML = request.responseTexts; ^^^^^^^^^^^^^^^^^^^^^
它應該是,
document.getElementById("testing").innerHTML = request.responseText;
查看頂部的<form>
元素,
<form class="regiForm" id="customerRegiForm" onsubmit="return formValidation()"> ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
但我在你的代碼中看不到formValidation()
函數。 創建一個名為formValidation()
的函數,並確保從該函數返回false
,否則每次單擊提交按鈕時都會提交表單。 所以,你的腳本應該是這樣的:
<script> function formValidation(){ var formNode = document.querySelector("#customerRegiForm"); var formData = new FormData(formNode); var request = new XMLHttpRequest(); request.open("POST", "post.php", true); request.onreadystatechange = function () { if(request.readyState == 4 && request.status == 200){ document.getElementById("testing").innerHTML = request.responseText; } }; request.send(formData); return false; } </script>
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