迭代字符串時C中的分段錯誤

Question

我是C的新手，我應該創建strtok函數。 問題是，我在這段代碼中不斷收到分段錯誤錯誤：

char *newstring = "testing, testing, tested."
while(*newstring != '\0' ){
    /*replace delimiters with nulls*/
    printf("STARTING ITERATION\n");
    if(*newstring ==','){
        *newstring='\0';
    }

    printf("newstring char in loop: %c\n", *newstring);
    /*printf("delimiters char in loop: %c\n", *delimiters);*/
    newstring++;
    printf("END OF ITERATION\n");
}
printf("OUT OF ITERATION");

因此輸出：

STARTING ITERATION
newstring char in loop: t
END OF ITERATION
STARTING ITERATION
newstring char in loop: e
END OF ITERATION
STARTING ITERATION
newstring char in loop: s
END OF ITERATION
STARTING ITERATION
newstring char in loop: t
END OF ITERATION
STARTING ITERATION
newstring char in loop:
END OF ITERATION
STARTING ITERATION
newstring char in loop: t
END OF ITERATION
STARTING ITERATION
newstring char in loop: e
END OF ITERATION
STARTING ITERATION
newstring char in loop: s
END OF ITERATION
STARTING ITERATION
newstring char in loop: t
END OF ITERATION
STARTING ITERATION
newstring char in loop:
END OF ITERATION
STARTING ITERATION
newstring char in loop: t
END OF ITERATION
STARTING ITERATION
newstring char in loop: e
END OF ITERATION
STARTING ITERATION
newstring char in loop: s
END OF ITERATION
STARTING ITERATION
newstring char in loop: .
END OF ITERATION
Segmentation fault (core dumped)

因此，看起來它一直到字符串的結尾和循環的結尾，但實際上並沒有使它成為循環的OUT。 我不確定我錯過了什么。

Answer 1

您正在嘗試修改C中不允許的字符串文字。如果更改char *newstring = "testing, testing, tested." to char newstring[] = "testing, testing, tested." ，然后你正在修改數組的內容。