如何使用angular 2.0.0忽略消毒錯誤/警告？

Question

在RC6之前，我這樣做：

    import { Injectable, provide, SecurityContext } from '@angular/core';
    import { DomSanitizationService } from '@angular/platform-browser';

    @Injectable()
    export class NoSanitizationService {
      sanitize(ctx: SecurityContext, value: any): string {
        return value;
      }
    }

    export const NO_SANITIZATION_PROVIDERS: any[] = [
      provide(DomSanitizationService, { useClass:         NoSanitizationService }),
    ];

我怎么能用新的角度釋放2.0.0做到這一點？ 因為我不能使用provide功能。

Answer 1

DomSanitizationService已重命名為DomSanitizer 。

import { Injectable, provide, SecurityContext } from '@angular/core';
import { DomSanitizer} from '@angular/platform-browser';

@Injectable()
export class NoSanitizationService {
  sanitize(ctx: SecurityContext, value: any): string {
    return value;
  }
}

export const NO_SANITIZATION_PROVIDERS: any[] = [
  {provide:DomSanitizer, useClass:NoSanitizationService },  //<----changed this line as well
]; 

---

import {NO_SANITIZATION_PROVIDERS} from 'valid path';

@NgModule({
  imports:      [ BrowserModule ],
  declarations: [ AppComponent ],
  bootstrap:    [ AppComponent ],
  providers:    [NO_SANITIZATION_PROVIDERS],                //<----here
})

Answer 2

不要導入提供並像這樣寫：

export const NO_SANITIZATION_PROVIDERS: any[] = [
    { provide: DomSanitizationService, useClass: NoSanitizationService }
];