將變量插入標題位置PHP 1

Question

問題是：如何在第16行的鏈接中插入變量$ conf_url作為標題的一部分：header（'Location：'$ conf_url.'index_back.php'）;

<?php
session_start();
include("conexao.php");

$email = $_POST['email'];
$senha = $_POST['senha'];

$query1 = mysqli_query($con, "SELECT * FROM usuario WHERE email = '$email' AND senha = '$senha'");
$row = $query1->fetch_row();
$_SESSION["iduser"] = $row[0];
$_SESSION["nome"] = $row[2];
$_SESSION["sobrenome"] = $row[3];
$_SESSION["img"] = $row[8];

if($query1->num_rows == 1){
    header('Location:' $conf_url.'index_back.php');
    //echo "<meta http-equiv='refresh' content='0, url= $conf_url/index_back.php'>";
}else{
    $_SESSION['error'] = 'Email e/ou senha invalido(s).';
    header('Location: '$conf_url'.'/login.php);
    //echo "<meta http-equiv='refresh' content='0, url= $conf_url/login.php'>";
}
?>

config.php
<?php
$conf_url = "http://localhost/production/";
?>

Answer 1

你可以這樣做

header("Location: " .$conf_url. "/login.php");

Answer 2

您只是錯過了'。'。 兩個header()函數中的連接標記，也弄亂了字符串文字。

if($query1->num_rows == 1){
    header('Location:' . $conf_url . '/index_back.php');

}else{
    $_SESSION['error'] = 'Email e/ou senha invalido(s).';
    header('Location: ' . $conf_url . '/login.php');

}

或在雙引號中使用變量擴展。

if($query1->num_rows == 1){
    header("Location: $conf_url/index_back.php");

}else{
    $_SESSION['error'] = 'Email e/ou senha invalido(s).';
    header("Location: $conf_url/login.php");

}