xcode 8 swift 3 圖像文件不會上傳到服務器

Question

使用 Xcode 8、Swift 3 和 PHP。

Xcode 和 PHP 運行沒有錯誤。

為什么模擬器中的 displayPic.image 沒有保存到服務器上的 pic1-1.png？ 出現的只是一個空白文件。

代碼：

@IBAction func sendToServer(_ sender: UIButton) {

    let url = NSURL(string: "http://www.example.com/picSaver.php")

    var request = URLRequest(url: url! as URL)

    request.httpMethod = "POST"

    var boundary = generateBoundaryString()

    request.setValue("multipart/form-data; boundary=\(boundary)", 
forHTTPHeaderField: "Content-Type")

    if (displayPic.image == nil)
    { return }

    let image_data = UIImagePNGRepresentation(displayPic.image!)
    var body = NSMutableData()
    let fname = "porch-167.png"
    let mimetype = "image/png"

    body.append("--\(boundary)\r\n".data(using: String.Encoding.utf8)!)
    body.append("Content-Disposition:form-data; 
name=\"photo\"\r\n\r\n".data(using: String.Encoding.utf8)!)
    body.append("Incoming\r\n".data(using: String.Encoding.utf8)!)
    body.append("--\(boundary)\r\n".data(using: String.Encoding.utf8)!)
    body.append("Content-Disposition:form-data; name=\"file\"; 
filename=\"\(fname)\"\r\n".data(using: String.Encoding.utf8)!)
    body.append("Content-Type: \(mimetype)\r\n\r\n".data(using: 
String.Encoding.utf8)!)
    body.append(image_data!)
    body.append("\r\n".data(using: String.Encoding.utf8)!)
    body.append("--\(boundary)--\r\n".data(using: 
String.Encoding.utf8)!)

    request.httpBody = body as Data

    let session = URLSession.shared

    let task = session.dataTask(with: request as URLRequest) {
        (
        data, response, error) in

        guard let _:Data = data, let _:URLResponse = response , error 
== nil else {
            print("error")
            return
            }

        let dataString = String(data: data!, encoding: 
String.Encoding(rawValue: String.Encoding.utf8.rawValue))
        print(dataString)

        }

    task.resume()
}

}

func generateBoundaryString() -> String {

return "Boundary-\(NSUUID().uuidString)"    
}

圖片保護程序

<?php
$p=$_REQUEST["filename"]
move_uploaded_file($p["tmp_name"], pic1-1.png);

$data=Array("Reply"=>"Image saved at server");
echo json_encode($data);
?>

“文件名”是 $p $_REQUEST 的正確參數請求嗎？

Answer 1

它現在完美無缺。 將 $_REQUEST 更改為 $_FILES，並將“文件名”更改為“文件”

<?php
$p=$_FILES["file"]
move_uploaded_file($p["tmp_name"], "pic1-1.png");

$data=Array("Reply"=>"Image saved at server");
echo json_encode($data);
?>