如何使方法和函數起作用-Javascript

Question

以下方法和功能不起作用，有人可以幫助我嗎？

hasMoreOscarsThan - this method accepts one actor object as a parameter and
    returns true if the actor has more Oscars than the one that is passed as
    a parameter and false otherwise.

現在編寫以下函數：

getActorByName - this function expects a string as a parameter and returns
    the object in the actors array whose name property is equal to the
    string that is passed in (if there is one).

我的代碼：

function Person(firstName, lastName, age, numOscars) {

    this.firstName = firstName;
    this.lastName = lastName;
    this.age = age;
    this.numOscars = numOscars;
    this.hello = function() { console.log("Hello, my name is " + this.firstName); }
    this.hasMoreOscarsThan = function(x, y) {
        if (this.numOscars > this.numOscars) {
            return this.firstName;
        } else {
            return "False!";
        }
    }

};


var actors = new Array();
actors[0] = new Person("Leonardo", "DiCaprio", 41, 1);
actors[1] = new Person("Jennifer", "Lawrence", 25, 1);
actors[2] = new Person("Samuel L.", " Jackson", 67, 0);
actors[3] = new Person("Meryl", "Streep", 66, 3);
actors[4] = new Person("John", "Cho", 43, 0);

actors.forEach(function(item) {
    item.hello();
})

actors.forEach(function(item) {
    item.hasMoreOscarsThan();
})


function getActorByName(person) {
    console.log(actors.firstName + " " + actors.lastName);
}


function list() {
    var actorsLength = actors.length;
    for (var i = 0; i < actorsLength; i++) {
        getActorByName(actors[i]);
    }
}


var search = function(lastName) {
    var actorsLength = actors.length;
    for (var i = 0; i < actorsLength; i++) {
        if (lastName == actors[i].lastName) {
            getActorByName(actors[i]);
        }
    }
}


search("DiCaprio");

var getAverageAge;

getAverageAge = (actors[0].age + actors[1].age + actors[2].age + actors[3].age + actors[4].age) / actors.length;
console.log(getAverageAge);

提前非常感謝您！！！

Answer 1

參數是person對象，但是您引用的是一些在函數內部未定義的actors ，因此更改為person.firstName和person.lastName

function getActorByName(person) {
    console.log(person.firstName + " " + person.lastName);
}

JSFIDDLE

Answer 2

我編輯了您的代碼：

function Person(firstName, lastName, age, numOscars) {

    this.firstName = firstName;
    this.lastName = lastName;
    this.age = age;
    this.numOscars = numOscars;
    this.hello = function() { console.log("Hello, my name is " + this.firstName); }
    this.hasMoreOscarsThan = function(x) { // x is a compare parameter
        if (this.numOscars > x) { // comparing numOscars with argument x
            return this.firstName;
        } else {
            return "False!";
        }
    }

};


var actors = new Array();
actors[0] = new Person("Leonardo", "DiCaprio", 41, 1);
actors[1] = new Person("Jennifer", "Lawrence", 25, 1);
actors[2] = new Person("Samuel L.", " Jackson", 67, 0);
actors[3] = new Person("Meryl", "Streep", 66, 3);
actors[4] = new Person("John", "Cho", 43, 0);

actors.forEach(function(item) {
    item.hello();
})

actors.forEach(function(item) {
    console.log(item.hasMoreOscarsThan(2)); // I put compare argument 2 and print result to console
})


function getActorByName(person) {
    console.log(person.firstName + " " + person.lastName); // changed actors to person
}


function list() {
    var actorsLength = actors.length;
    for (var i = 0; i < actorsLength; i++) {
        getActorByName(actors[i]);
    }
}


var search = function(lastName) {
    var actorsLength = actors.length;
    for (var i = 0; i < actorsLength; i++) {
        if (lastName == actors[i].lastName) {
            getActorByName(actors[i]);
        }
    }
}


search("DiCaprio");

var getAverageAge;

getAverageAge = (actors[0].age + actors[1].age + actors[2].age + actors[3].age + actors[4].age) / actors.length;
console.log(getAverageAge);

結果是：

你好，我叫萊昂納多

你好，我叫詹妮弗

您好，我叫塞繆爾·L。

你好，我叫梅麗爾

你好，我的名字是約翰

假！ 假！
假！
梅麗爾
假！
萊昂納多·迪卡普里奧48.4