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sequelize hasMany,如何使用自定義的foreginKey

[英]sequelize hasMany, how to use customized foreginKey

模型EmployeeView

module.exports = function(sequelize, DataTypes) {
  var _this = sequelize.define('EmployeeView', {
    employeeId: {
      type: DataTypes.INTEGER,
      field: 'code'
    },
    username: DataTypes.STRING,
    email: {
      type: DataTypes.STRING,
      field: 'emailaddress'
    },
    department: {
      type: DataTypes.STRING,
      field: 'department_name'
    },
    departmentId: {
      type: DataTypes.STRING,
      field: 'departments_id'
    }
  }, {
    timestamps: false,
    freezeTableName: true,
    tableName: 'employees_view',
    classMethods: {
      associate: function(models) {
        _this.belongsTo(models.EmployeeCategory, {
          foreignKey: {
            name: 'employeecategories_id'
          }
        });
        _this.hasMany(models.EmployeeFile, {
          foreignKey: 'employees_code'
        });
      }
    }
  });
  return _this;
};

模型EmployeeFile

module.exports = function(sequelize, DataTypes) {
  var _this = sequelize.define("EmployeeFile", {
    employeeId: {
      type: DataTypes.INTEGER,
      field: 'employees_code'
    },
    filename: {
      type: DataTypes.STRING,
      filed: 'filename'
    },
    employeeFileTypeId: {
      type: DataTypes.INTEGER,
      field: 'employee_file_types_id'
    }
  }, {
    timestamps: false,
    freezeTableName: true,
    tableName: 'employee_files'
  });

  return _this;
};

路由器

router.get('/employee', function(req, res) {
  models.EmployeeView.findAll({
    where: {
      active: req.query.active
    }
    include: [{
      model: models.EmployeeCategory
    }, {
      model: models.EmployeeFile,
       }]
  }).then(function(employee) {
    res.json(employee);
  });
});

我期待發生什么?

我有兩個表' employee_view '( 它是一個視圖 )和' employee_files ',它們映射到' EmployeeView '和' EmployeeFile '。 ' employee_view '將' id '字段作為主鍵,將' code '字段作為員工編號。 employee_files '有' employees_code '作為主鍵,foreignKey與' code '字段綁定。 所以我希望通過這種關系得到' employee_files '數據。

究竟發生了什么?

實際上,我一無所獲。 因為sequelize將執行“EmployeeView.id == EmployeeFile.employees_code”。 但我希望sequelize執行“EmployeeView.code == EmployeeFile.employees_code”。我該怎么辦?

只需將primaryKey: true添加到employeeId字段即可將EmployeeView鏈接到EmployeeFiles,因為belongsToMany關系只鏈接到它的父級的主鍵

employeeId: {
  type: sequelize.INTEGER,
  field: 'code',
  primaryKey: true
},

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