xcode swift 3.0 解析 JSON 響應

Question

我正在嘗試獲取狀態代碼並將其放入 if 語句中。 此代碼將在 xCode 游樂場中運行。

現在狀態返回為["200"]並用方括號括起來。 如果我刪除括號，它會返回nil 。

如何將狀態返回為 200 並將其放入 if 語句中？

import Foundation

let str = "{\"names\": [\"Bob\", \"Tim\", \"Tina\"],\"status\"[\"200\"],\"message\":\"User has been  created\",\"id\":null,\"username\":\"asdf\"}"//"{\"names\": [\"Bob\", \"Tim\", \"Tina\"]}"
let data = str.data(using: String.Encoding.utf8, allowLossyConversion: false)!

do {
     let json = try JSONSerialization.jsonObject(with: data, options: []) as! [String: AnyObject]
     let status = json["status"] as? [String]

} catch let error as NSError {
    print("Failed to load: \(error.localizedDescription)")
}

Answer 1

您可以嘗試以下解決方法：

let responseString = Optional("{\"status\":\"200\",\"message\":\"User has been created\",\"id\":null,\"username\":\"asdf\"}")
let responseData = responseString?.data(using: .utf8)
let dict: Dictionary<String, Any> = try JSONSerialization.jsonObject(with: responseData!, options: []) as! Dictionary<String, Any>

let status = dict["status"] // optional value stored with "status" key in Dictionary

似乎實際上，Swift 3 拒絕使用以下方法進行編譯：

let dict: Dictionary<String, Any> = try JSONSerialization.jsonObject(with: responseString?.data(using: .utf8)!, options: []) as! Dictionary<String, Any>

Swift 3 聲稱 responseString?.data(using: .utf8)！ 應該打開，盡管它已經打開了。

Answer 2

let str = "{\"names\": [\"Bob\", \"Tim\", \"Tina\"],\"status\":[\"200\"],\"message\":\"User has been  created\",\"id\":null,\"username\":\"asdf\"}"//"{\"names\": [\"Bob\", \"Tim\", \"Tina\"]}"
let data = str.data(using: .utf8)

do {
    let json = try JSONSerialization.jsonObject(with: data!, options: []) as! [String: AnyObject]
    let status = json["status"] as? [String]
    let yourValue =  status?[0]

} catch let error as NSError {
    print("Failed to load: \(error.localizedDescription)")
}

我只是在 json 格式的狀態后添加 (:) 無效