用GKRandomSource生成隨機數

Question

我在結構中使用GKRandomSource在視圖中返回隨機的鼓舞人心的報價。 有沒有辦法返回該隨機數並忽略先前的輸入？ 這樣，用戶不會連續兩次收到相同的報價。

let inspiration = [
    "You are looking rather nice today, as always.",
    "Hello gorgeous!",
    "You rock, don't ever change!",
    "Your hair is looking on fleek today!",
    "That smile.",
    "Somebody woke up on the right side of bed!"]

func getRandomInspiration() -> String {
    let randomNumber = GKRandomSource.sharedRandom().nextIntWithUpperBound(inspiration.count)
    return inspiration[randomNumber]
}

Answer 1

為了避免產生相同的報價，請在名為lastQuote的struct屬性中跟蹤最后一個lastQuote 。 然后將最大隨機數減1，如果生成的結果與lastQuote相同，則使用max代替。

struct RandomQuote {
    let inspiration = [
        "You are looking rather nice today, as always.",
        "Hello gorgeous!",
        "You rock, don't ever change!",
        "Your hair is looking on fleek today!",
        "That smile.",
        "Somebody woke up on the right side of bed!"]

    var lastQuote = 0

    mutating func getRandomInspiration() -> String {
        let max = inspiration.count - 1
        // Swift 3
        // var randomNumber = GKRandomSource.sharedRandom().nextInt(upperBound: max)
        var randomNumber = GKRandomSource.sharedRandom().nextIntWithUpperBound(max)
        if randomNumber == lastQuote {
            randomNumber = max
        }
        lastQuote = randomNumber
        return inspiration[randomNumber]
    }
}

var rq = RandomQuote()
for _ in 1...10 {
    print(rq.getRandomInspiration())
}