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[英]unzip a specific file in the zip file uploaded by sp using java and google app engine
[英]how to unzip an uploaded zip file using spring in java
我正在從屏幕上傳zip文件夾,並使用MultipartFile將其發送到contoller。我正在嘗試提取上載的文件夾並將提取的文件夾保存在某個特定位置..我嘗試了但我沒有得到....有人可以建議我? 這是我的代碼
public String test(
@RequestParam("datafile") MultipartFile file
{
String source =file.getOriginalFilename();
//source variable will containthe value as "zip_Folder.zip";
String destination = "D:\\destination";
try {
ZipFile zipFile = new ZipFile(source);
zipFile.extractAll(destination);
} catch (ZipException e) {
e.printStackTrace();
}
}
必需的zip4j和Apache Commons-IO依賴項:
@PostMapping("/upload")
public String add(@RequestParam("file") MultipartFile file) throws IOException {
/**
* save file to temp
*/
File zip = File.createTempFile(UUID.randomUUID().toString(), "temp");
FileOutputStream o = new FileOutputStream(zip);
IOUtils.copy(file.getInputStream(), o);
o.close();
/**
* unizp file from temp by zip4j
*/
String destination = "D:\\destination";
try {
ZipFile zipFile = new ZipFile(zip);
zipFile.extractAll(destination);
} catch (ZipException e) {
e.printStackTrace();
} finally {
/**
* delete temp file
*/
zip.delete();
}
return "redirect:/";
}
除此之外,最好的方法是在屬性文件中放置“ D:\\ destination”之類的常量,並通過@Value注入
@Value("${destination.dir}")
private String destination;
嘗試使用
java.util.zip.ZipEntry; java.util.zip.ZipInputStream;
為我工作
例
https://www.mkyong.com/java/how-to-decompress-files-from-a-zip-file/
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