[英]How to sort a list of dictionaries by the value of a key and by the value of a value of a key?
{
"states": [
{
"timestamp": {
"double": 968628281.0
},
"sensorSerialNumber": 13020235
},
{
"timestamp": {
"double": 964069109.0
},
"sensorSerialNumber": 13020203
},
{
"timestamp": {
"double": 9641066.0
},
"sensorSerialNumber": 30785
}
]
}
有沒有一種方法可以通過“ sensorSerialNumber”和“ timestamp”(9.68628281E8)值中的此數字對字典列表進行排序,
"timestamp":{"double":9.68628281E8}
使用內置函數(已排序 )
from operator import itemgetter
newlist = sorted(list_to_be_sorted, key=itemgetter('name'))
但是,我的問題與其他問題略有不同 。 如果字典中沒有字典,則只需將第二個鍵的字符串添加到內置函數中,例如:
from operator import itemgetter
newlist = sorted(list_to_be_sorted, key=itemgetter('name', 'age'))
key
可以是任何可調用key
,它依次傳遞給list_to_be_sorted
中的每個元素。 因此, lambda
將適合此處:
newlist = sorted(
data['states'],
key=lambda i: (i['sensorSerialNumber'], i['timestamp']['double']))
因此,lambda返回'sensorSerialNumber'
鍵的值作為元組的第一個元素,並從'timestamp'
鍵的字典值中返回'double'
鍵的值。
演示:
>>> data = {"states" :
... [{"timestamp":{"double":9.68628281E8},"sensorSerialNumber":13020235},
... {"timestamp":{"double":9.64069109E8},"sensorSerialNumber":13020203},
... {"timestamp":{"double":9641066.0},"sensorSerialNumber":30785}]
... }
>>> sorted(data['states'], key=lambda i: (i['sensorSerialNumber'], i['timestamp']['double']))
[{'timestamp': {'double': 9641066.0}, 'sensorSerialNumber': 30785}, {'timestamp': {'double': 964069109.0}, 'sensorSerialNumber': 13020203}, {'timestamp': {'double': 968628281.0}, 'sensorSerialNumber': 13020235}]
>>> from pprint import pprint
>>> pprint(_)
[{'sensorSerialNumber': 30785, 'timestamp': {'double': 9641066.0}},
{'sensorSerialNumber': 13020203, 'timestamp': {'double': 964069109.0}},
{'sensorSerialNumber': 13020235, 'timestamp': {'double': 968628281.0}}]
該演示沒有那么有意義,因為沒有相等的序列號來包含時間戳記值以產生影響。
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