Bash按范圍分割CSV

Question

我有以下CSV文件

"Costa Rica","Aberdeen Research",10152
"Costa Rica","Applebees Lab",14562
"Costa Rica","Bride Research",10452
"Costa Rica","Complex Teams",4512
"Costa Rica","Dynamic Air",7854
"Costa Rica","Electronict Arts",7851

而且我需要根據BASH腳本中第二列的第一個字符在N個新文件中拆分CSV

例如腳本：

$: ./split.sh -from A -to C file.csv

預期結果必須是：

"Costa Rica","Aberdeen Research",10152
"Costa Rica","Applebees Lab",14562
"Costa Rica","Bride Research",10452
"Costa Rica","Complex Teams",4512

依此類推，如果我在-from -to參數中傳遞了不同的首字母

謝謝

Answer 1

您可以使用awk輕松完成類似的操作。

awk -F "," '$2 ~ /^\"[A-C]/' < file.csv

將返回：

"Costa Rica","Aberdeen Research",10152
"Costa Rica","Applebees Lab",14562
"Costa Rica","Bride Research",10452
"Costa Rica","Complex Teams",4512

請注意，這是區分大小寫的，因此不會匹配"Costa Rica","bird sanctuary",4321 。 為此，將命令更改為：

awk -F "," '$2 ~ /^\"[a-cA-C]/' < file.csv

使它適應bash腳本應該足夠簡單，請考慮對awk，getopts和正則表達式匹配進行一些閱讀。