調用 Void 方法將整數打印為文本

Question

我對在oneDigit方法的參數中oneDigit什么以及在調用oneDigit method的 main 方法中放入什么感到困惑，以便用單詞（四oneDigit method打印出四位整數 4321。 任何幫助將非常感激！

import javax.swing.JOptionPane;

public class ToEnglish {

   public static void oneDigit(int n1, int n2, int n3, int n4){

   }//end oneDigit

    public static void main(String[] args) {

      int number;
      int n1;
      int n2;
      int n3;
      int n4;
      String input;

      JOptionPane.showMessageDialog(null,
                                   "Welcome to the ToEnglish program by Josh Higgins!",
                                   "ToEnglish",
                                   JOptionPane.PLAIN_MESSAGE);
      input = JOptionPane.showInputDialog(null,
                                               "Please enter a four-digit integer",
                                               "ToEnglish",
                                               JOptionPane.QUESTION_MESSAGE);
      number = Integer.parseInt(input);

      //breaking integer up into 4 digits
      n1 = number / 1000;
      int n1Remainder = number % 1000;
      n2 = n1Remainder / 100;
      int n2Remainder = number % 100;
      n3 = n2Remainder / 10;
      int n3Remainder = number % 10;
      n4 = number % 10;

      if
      (number < 0000 || number > 9999) { 
         System.out.println("Invalid input");
      }
      else {
      n1 = number / 1000;
      n1Remainder = number % 1000;
      n2 = n1Remainder / 100;
      n2Remainder = number % 100;
      n3 = n2Remainder / 10;
      n3Remainder = number % 10;
      n4 = number % 10;
      }

      if ((number > 0000) && (number < 9999)) {
      System.out.println(n1 + " " + n2 + " " + n3 + " " + n4 + " ");
      }
      else {
      System.out.println("Invalid input");
      }

      //invoking oneDigit Method in order to print the four digit integer in text
      oneDigit(n1);
      oneDigit(n2);
      oneDigit(n3);
      oneDigit(n4);

 System.out.println("All done for now!");
      System.exit(0);

   }//end of the main method

}//end of the class

---

@Vishal，這是我改進的代碼，但是當我運行它時，我只得到 4 3 2 1，而不是文本。 有什么建議？

import javax.swing.JOptionPane;

public class ToEnglish {

   public void oneDigit(int digit){

   }//end oneDigit

    public static void main(String[] args) {

      int digit=0;
      int number;
      int n1;
      int n2;
      int n3;
      int n4;
      String input;

      JOptionPane.showMessageDialog(null,
                                   "Welcome to the ToEnglish program by Josh Higgins!",
                                   "ToEnglish",
                                   JOptionPane.PLAIN_MESSAGE);
      input = JOptionPane.showInputDialog(null,
                                               "Please enter a four-digit integer",
                                               "ToEnglish",
                                               JOptionPane.QUESTION_MESSAGE);
      number = Integer.parseInt(input);

      //breaking integer up into 4 digits
      n1 = number / 1000;
      int n1Remainder = number % 1000;
      n2 = n1Remainder / 100;
      int n2Remainder = number % 100;
      n3 = n2Remainder / 10;
      int n3Remainder = number % 10;
      n4 = number % 10;

      if
      (number < 0000 || number > 9999) { 
         System.out.println("Invalid input");
      }
      else {
      n1 = number / 1000;
      n1Remainder = number % 1000;
      n2 = n1Remainder / 100;
      n2Remainder = number % 100;
      n3 = n2Remainder / 10;
      n3Remainder = number % 10;
      n4 = number % 10;
      }

      if ((number > 0000) && (number < 9999)) {
      System.out.println(n1 + " " + n2 + " " + n3 + " " + n4 + " ");
      }
      else {
      System.out.println("Invalid input");
      }

      switch (digit) {
         case 1 : System.out.print("One");
         break;
         case 2 : System.out.print("Two");
         break;
         case 3 : System.out.print("Three");
         break;
         case 4 : System.out.print("Four");
         break;
         case 5 : System.out.print("Five");
         break;
         case 6 : System.out.print("Six");
         break;
         case 7 : System.out.print("Seven");
         break;
         case 8 : System.out.print("Eight");
         break;
         case 9 : System.out.print("Nine");
         break;
       }

 System.out.println("All done for now!");
      System.exit(0);

   }//end of the main method

}//end of the class

Answer 1

根據您的方法原型， oneDigit 方法接受四個整數，並且您只使用一個整數調用了該方法。 您可以使用一個參數編寫該方法。 在該方法內部，使用帶有參數的 switch case 以單詞為單位打印數字。

例如：這段代碼應該寫在 oneDigit 方法里面

public static void oneDigit(int digit) {
    switch(digit) {
        case 1 : System.out.print("One");
                 break;
        //Other cases followed
}

你可以用所有的數字來跟隨這個。

或者您可以編寫一個 if-else if 塊來檢查傳遞給該方法的整數並在該塊中以單詞形式打印數字。

編輯：代碼塊

Answer 2

嘗試這個：

public static String oneDigit(int digit){
  switch(digit){
    case 0:
    return "zero";
    case 1:
    return "one";
    //add missing cases
    default:
    return "not in range"; //you can throw an exception here if you prefer
  }
}