蘋果通知設備令牌更改

Question

更新我的應用程序后，我遇到了問題。 我正在以這種格式C43461D5-E9CB-4C10-81F8-020327A07A62獲取設備令牌，並且通知無法正常工作。

之前，我收到過以下格式的通知： 2add70865401171c7ca1d3b3957b719eaf721fef8f8d7a52bc91ef8a872cc004

我確實允許該應用的通知，但我在后端沒有做任何更改。 誰能指導我為什么它不起作用？

didFinishLaunchingWithOptions代碼：

if ([[[UIDevice currentDevice] systemVersion] floatValue] >= 8.0)
{
    [[UIApplication sharedApplication] registerUserNotificationSettings:[UIUserNotificationSettings settingsForTypes:(UIUserNotificationTypeSound | UIUserNotificationTypeAlert | UIUserNotificationTypeBadge) categories:nil]];
    [[UIApplication sharedApplication] registerForRemoteNotifications];
}
else
{
    [[UIApplication sharedApplication] registerForRemoteNotificationTypes:
     (UIUserNotificationTypeBadge | UIUserNotificationTypeSound | UIUserNotificationTypeAlert)];
}

獲取設備令牌：

NSString *deviceTokenID = [[NSUserDefaults standardUserDefaults] objectForKey:DEVICE_TOKEN_PUSH_NOTI];
if ([deviceTokenID isEqualToString:@""] || deviceTokenID == nil) {
    NSString *tempApplicationUUID  = [[[UIDevice currentDevice] identifierForVendor] UUIDString];
    [dics setObject:tempApplicationUUID forKey:@"cust_device_id"];
} else {
    [dics setObject:[[NSUserDefaults standardUserDefaults] objectForKey:DEVICE_TOKEN_PUSH_NOTI] forKey:@"cust_device_id"];
}

我收到以下錯誤：

代碼= 3000“找不到適用於應用程序的有效“ aps-environment”授權字符串” UserInfo = {NSLocalizedDescription =找不到適用於應用程序的有效“ aps-environment”授權字符串}，找不到適用於應用程序的有效“ aps-environment”授權字符串

Answer 1

請前往

單擊.xcodeproj->功能->啟用推送通知

希望它能工作

Answer 2

單擊.xcodeproj->功能->啟用推送通知

Answer 3

NSString *tempApplicationUUID  = [[[UIDevice currentDevice] identifierForVendor] UUIDString];

UUIDString是唯一設備ID，但對於Apple Push Notification，您需要從APNS取回設備令牌，因此使用以下方法，您將獲得64位deviceToken並獲取通知。

-(void)application:(UIApplication *)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken


{
    NSString *devToken = [[[[deviceToken description]
                            stringByReplacingOccurrencesOfString:@"<"withString:@""]
                           stringByReplacingOccurrencesOfString:@">" withString:@""]
                          stringByReplacingOccurrencesOfString: @" " withString: @""];


    NSString *str = [NSString
                     stringWithFormat:@"Device Token=%@",devToken];

    [[NSUserDefaults standardUserDefaults]setObject:devToken forKey:@"DeviceToken"];

}