無法在PHP上獲得變量

Question

嘿!
我試圖理解為什么這段代碼不起作用：

public static function selectUser($connection, $userid){

        require_once 'UserRepository.inc.php';

        if(!isset($connection) || !isset($userid)){
            return;
        }

        $result = mysqli_query($connection, "SELECT * FROM users WHERE id = ".$userid."");
        $row = mysqli_fetch_assoc($result);

        $user = new User($userid, 
                $row["email"], 
                $row["cp_username"],
                $row["mc_username"],
                $row["forum_username"],
                $row["password"],
                $row["avatarurl"]);

        return $user;


    }

基本上，這應該做的是當你創建一個變量（ $user = UserMan::selectUser(Connection::getConnection(), $_COOKIE["uid"]) ）並嘗試召喚一個get數據屬性（ $user->getCpUsername() ）它不起作用。 現在我的頁面看起來像這樣：
我的頁面現在看起來像的形象
我需要在那里打印名稱。 我不確定我做錯了什么。
謝謝你耐心等待。 祝你有美好的一天！

---

編輯：

  class User { private $id; private $email; private $cp_username; private $mc_username; private $forum_username; private $password; private $avatarurl; public function __construct($id, $email, $cp_username, $mc_username, $forum_username, $password, $avatarurl) { $this->id = $id; $this->email = $email; $this->cp_username = $cp_username; $this->mc_username = $mc_username; $this->forum_username = $forum_username; $this->password = $password; $this->avatarurl = $avatarurl; } public function getId(){ return $this->id; } public function getEmail(){ return $this->email; } public function getCpUsername(){ return $this->cp_username; } public function getMcUsername(){ return $this->mc_username; } public function getForumUsername(){ return $this->forum_username; } public function getPassword(){ return $this->password; } public function getAvatarurl(){ return $this->avatarurl; } public function setEmail($email){ $this->email = $email; } public function setCpUsername($username){ $this->cp_username = $username; } public function setMcUsername($username){ $this->mc_username = $username; } public function setForumUsername($username){ $this->forum_username = $username; } public function setPassword($password){ $this->password = $password; } public function setAvatarurl($avatarurl){ $this->avatarurl = $avatarurl; } } 

Answer 1

嘗試改變

$row = mysqli_fetch_assoc($result);

至

$row = mysqli_fetch_assoc($result)[0];