您如何檢查給定的句子在Java中是否回避某個字母？

Question

我一直在試圖弄清楚如何查看給定的句子是否是避免使用字母E的口形圖。我已經達到了輸入真假陳述的地步，但是只輸出了“此句子不是口形圖”每次輸入是否包含e時都應避免使用字母e。“。 我究竟做錯了什么？

boolean avoidsE = false, hasE = true, avoidsS = false, containsS = true;

for(int i = 0; i < sentence.length(); i++)
{
  if (sentence.charAt(i) == 'e')
  hasE = true;
  else
  avoidsE = false;
}

if (hasE = true)
System.out.println("This sentence is not a Lipogram avoiding the letter e. ");
else if (avoidsE = false)
System.out.println("This sentence is a Lipogram avoiding the letter e! ");

Answer 1

if (hasE == true) // "=" is to assign, you want to use "==" here to check  
    System.out.println("This sentence is not a Lipogram avoiding the letter e. "); 
else if (avoidsE == false) //same here   
    System.out.println("This sentence is a Lipogram avoiding the letter e! ");

Answer 2

如果要比較某項，則應使用雙等於==

要搜索字符串中是否包含字符，可以使用contains方法；要檢查字符串中是否不包含字母，可以使用indexOf 。 就像這樣：

public static void main(String[] args) {
    String sentence = "This is your sentence";

    if(sentence.contains("e")){
        System.out.println("This sentence is not a Lipogram avoiding the letter e. ");
    }
    else if("e".indexOf(sentence) < 0){
        System.out.println("This sentence is a Lipogram avoiding the letter e!");
    }
}

Answer 3

無需在這里重新發明輪子。

public class Main {
    public static void main(String[] args) {
        System.out.println(hasChar("asdfe", 'e'));
        System.out.println(hasChar("asdfghij", 'e'));
    }

    static boolean hasChar(String str, char c) {
        return str.chars().anyMatch(x -> x == c);
    }
}

輸出：

true
false