Python-如何從列表中的許多詞典中打印某個詞典字段？

Question

我目前正在研究喜歡游戲的Guess Who，但我似乎無法使其正常工作。 我想做的是從列表中下面所有詞典中打印“名稱”字段。

 Greg = {"Name":"Greg", "HairLength":"Short", "HairColour":"Brown", "FacialHair":"Yes", "Jewellery":"Yes", "Hat":"No", "Lipstick":"No", "Gender":"Male"}

 Chris = {"Name":"Chris", "HairLength":"Long", "HairColour":"Blonde", "FacialHair":"No", "Jewellery":"No","Hat":"Yes", "Lipstick":"Yes", "Gender":"Male"}

 Jason = {"Name":"Jason", "HairLength":"Short", "HairColour":"Brown", "FacialHair":"Yes", "Jewellery":"No","Hat":"Yes", "Lipstick":"No", "Gender":"Male"}

 Clancy = {"Name":"Clancy", "HairLength":"Bald", "HairColour":"Red", "FacialHair":"Yes", "Jewellery":"No", "Hat":"No","Lipstick":"No", "Gender":"Male"}

 Betty = {"Name":"Betty", "HairLength":"Short", "HairColour":"Blonde", "FacialHair":"No", "Jewellery":"Yes","Hat":"Yes", "Lipstick":"Yes", "Gender":"Female"}

 Helen = {"Name":"Helen", "HairLength":"Short", "HairColour":"Brown", "FacialHair":"No", "Jewellery":"No", "Hat":"No","Lipstick":"Yes", "Gender":"Female"}

 Selena = {"Name":"Selena", "HairLength":"Long", "HairColour":"Brown", "FacialHair":"No", "Jewellery":"Yes","Hat":"No", "Lipstick":"No", "Gender":"Female"}

 Jacqueline = {"Name":"Jacqueline", "HairLength":"Long", "HairColour":"Red", "FacialHair":"Yes", "Jewellery":"Yes", "Hat":"No","Lipstick":"No", "Gender":"Female"}


AISuspects = ([Greg, Chris, Jason, Clancy, Betty, Selena, Helen,
Jacqueline])
UserSuspects = ([Greg, Chris, Jason, Clancy, Betty, Selena, Helen, Jacqueline])

print("AISuspects:")
#Here i want it to print the field "Name" in every dictionary within the list AISuspects 


print("UserSuspects:")
#Here i want it to print the field "Name" in every dictionary within the list UserSuspects

解決后的預期輸出和電流輸出：

AI嫌疑犯：['Greg'，'Chris'，'Jason'，'Clancy'，'Betty'，'Selena'，'Helen'，'Jacqueline']

用戶嫌疑犯：['Greg'，'Chris'，'Jason'，'Clancy'，'Betty'，'Selena'，'Helen'，'Jacqueline']

Answer 1

您可以使用列表理解來獲取所有嫌疑人姓名的列表

suspects_names = [suspect['Name'] for suspect in AISuspects]

然后可以使用print(' '.join(suspect_names))

如果您不介意在新行中打印每個名稱，請使用for循環：

for suspect in AISuspects:
    print(suspect['Name'])

請注意列表定義周圍的那些括號，您不需要它們，它們通常用於定義元組，因此我將擺脫它們

Answer 2

UserSuspects = [Greg['Name'], Chris['Name'],Jason['Name'], Clancy['Name'], Betty['Name'], Selena['Name'], Helen['Name'], Jacqueline['Name']]


print UserSuspects