Java Spring REST Get工作得很好，但是當發布json時我得到404錯誤

Question

我遇到了Spring REST Web服務的問題。 當我嘗試發布JSON時，我總是得到404錯誤。 獲取請求工作正常，但不發布。 在互聯網上搜索但找不到類似的問題。 也許你們可以幫助我。 這是我的代碼：

控制器：

package com.java.rest;
import com.java.dto.IncomingTemperature;
import com.java.dto.SensorsTemperature;
import com.java.service.GetSensorsTemperature;
import com.java.service.TemperatureService;
import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.http.HttpStatus;
import org.springframework.http.ResponseEntity;
import org.springframework.web.bind.annotation.*;


@RestController
@RequestMapping("/rest")
public class TemperatureRestController {

final static Logger logger = LoggerFactory.getLogger(TemperatureRestController.class);

@Autowired
TemperatureService temperatureService;
@Autowired
GetSensorsTemperature sensorService;

@RequestMapping(value = "/temperature", method = RequestMethod.POST, produces = "application/json")
@ResponseBody
public ResponseEntity<?> addTemperature(@RequestBody IncomingTemperature temperature){
    logger.info("Temperature: {} recieved", temperature);
    temperatureService.addTemperature(temperature);
    return new ResponseEntity<HttpStatus>(HttpStatus.CREATED);
}

@RequestMapping(value = "/temperature/{sensorId}", method = RequestMethod.GET, produces = "application/json")
public SensorsTemperature getTemperature(@PathVariable("sensorId") Long sensorId){
    logger.info("Getting temperatures for sensor{}", sensorId);
    return sensorService.getSensorsTemperature(sensorId);
}

}

模型：

package com.java.dto;


import com.fasterxml.jackson.annotation.JsonFormat;

import java.io.Serializable;
import java.util.Date;

public class IncomingTemperature implements Serializable{

    private long sensorId;

    private double temperature;

    @JsonFormat(shape= JsonFormat.Shape.STRING, pattern="yyyy-MM-dd HH:mm:ss")
    private Date date;

    public long getSensorId() {
        return sensorId;
    }

    public void setSensorId(long sensorId) {
        this.sensorId = sensorId;
    }

    public double getTemperature() {
        return temperature;
    }

    public void setTemperature(double temperature) {
        this.temperature = temperature;
    }

    public Date getDate() {
        return date;
    }

    public void setDate(Date date) {
        this.date = date;
    }

pom.xml中：

 <?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>

    <groupId>com.java</groupId>
    <artifactId>knowyourheat</artifactId>
    <version>0.0.1-SNAPSHOT</version>
    <packaging>jar</packaging>

    <name>KnowYourHeat</name>
    <description>Application for temperature monitoring</description>

    <parent>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-parent</artifactId>
        <version>1.4.0.RELEASE</version>
        <relativePath/> <!-- lookup parent from repository -->
    </parent>

    <properties>
        <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
        <project.reporting.outputEncoding>UTF-8</project.reporting.outputEncoding>
        <java.version>1.8</java.version>
    </properties>

    <dependencies>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-data-jpa</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-security</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-thymeleaf</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-web</artifactId>
        </dependency>

        <dependency>
            <groupId>mysql</groupId>
            <artifactId>mysql-connector-java</artifactId>
            <scope>runtime</scope>
        </dependency>

        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-mail</artifactId>
        </dependency>

        <dependency>
            <groupId>javax.mail</groupId>
            <artifactId>mail</artifactId>
            <version>1.4.3</version>
        </dependency>

        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-test</artifactId>
            <scope>test</scope>
        </dependency>
    </dependencies>

    <build>
        <plugins>
            <plugin>
                <groupId>org.springframework.boot</groupId>
                <artifactId>spring-boot-maven-plugin</artifactId>
            </plugin>
        </plugins>
    </build>


</project>

我發布的Json：

{
 "sensorId" : 1,
 "temperture" : 20,
 "date" : "2016-10-20 22:10:10"
}

編輯：

我得到的錯誤：

 {
  "timestamp": 1477601444227,
  "status": 404,
  "error": "Not Found",
  "message": "No message available",
  "path": "/rest/temperature/"
}

先感謝您！

編輯2：

我剛剛使用相同的控制器創建了新項目，一切正常。 正如我發現問題是彈簧安全性，出於某種原因，即使我允許所有請求，Post和Put方法也不起作用。 這就是我的問題。

Answer 1

嘗試在@RequestMapping中添加“consumemes =”application / json“，如下所示：

@RequestMapping(value = "/temperature", method = RequestMethod.POST, produces = "application/json", consumes="application/json")

Answer 2

嘗試在RequestMapping中添加“headers =”Accept = application / json“”，如下所示：

@RequestMapping(value = "/temperature", method = RequestMethod.POST, headers = "Accept=application/json")

Answer 3

使用@RestController ，方法中不需要@ResponseBody 。 你得到404因為該方法不能接受任何類型的身體內容。 當該方法僅從HTTP請求接收內容但未發回任何正文內容時，您只需要consumes 。 ResponseEntity<xxx>定義除HttpStatus之外該方法將返回的正文內容。 如果它沒有返回正文內容而只返回HttpStatus，則必須使用ResponseEntity<Void> 。 請嘗試以下方法

@RequestMapping(value = "/temperature", method = RequestMethod.POST, consumes = MediaType.APPLICATION_JSON_VALUE)
public ResponseEntity<Void> addTemperature(@RequestBody IncomingTemperature temperature){
    logger.info("Temperature: {} recieved", temperature);
    temperatureService.addTemperature(temperature);
    return new ResponseEntity<Void>(HttpStatus.CREATED);
}

現在你應該在客戶端獲得HttpStatus 201 Created 。