從派生表中提取列並將它們加到一個MySQL SELECT語句中

Question

我需要從兩個表中提取列數據，對數據進行計算並將結果另存為別名，然后將這些結果求和成其他別名以顯示在php表中。 我正在嘗試通過在SELECT語句中創建派生表來實現此目的，但是它不起作用。 我沒有收到任何錯誤，但是我的表僅顯示列標題。

碼：

$sql = "SELECT x.company, x.stagestatus, x.shippeddate, SUM(x.totprice) as totalprice, SUM(x.sgtotquantity) as sgtotqty, SUM(x.sgtotalsqft) as sgtotsqft, SUM(x.avgsqftrev) as avgsqftrevenue, SUM(x.avgunitrev) as avgunitrevenue FROM (SELECT t1.company, t1.stagestatus, t1.shippeddate, t1.id, FORMAT(TRIM(LEADING '$' FROM t1.totalprice), 2) AS totprice, t2.invoiceid, SUM(t2.quantity) AS sgtotqauntity, FORMAT(SUM(t2.width * t2.height * t2.quantity ) /144, 2) AS sgtotalsqft, FORMAT((TRIM(LEADING '$' FROM t1.totalprice)/(SUM(t2.width * t2.height * t2.quantity ) /144)), 2) as avgsqftrev, FORMAT((TRIM(LEADING '$' FROM t1.totalprice) / SUM(t2.quantity)), 2) AS avgunitrev
  FROM invoices AS t1 INNER JOIN lineitems AS t2 ON t1.id = t2.invoiceid
  WHERE (t2.invoiceid = t1.id)
  GROUP BY t1.id) x
WHERE x.stagestatus='Complete'
GROUP BY x.company ASC";

這段代碼中斷了，但是當我單獨使用較小的代碼時，它可以正常工作。

例如：

$sql="SELECT invoices.id, invoices.orderdate, invoices.stagestatus, FORMAT(TRIM(LEADING '$' FROM invoices.totalprice), 2) AS totalprice, clients.company, lineitems.invoiceid, SUM(lineitems.quantity) AS sgtotqty, FORMAT(SUM(lineitems.width * lineitems.height * lineitems.quantity ) /144, 2) AS sgtotsqft, FORMAT((TRIM(LEADING '$' FROM invoices.totalprice)/(SUM(lineitems.width * lineitems.height * lineitems.quantity ) /144)), 2) as avgsqftrevenue, FORMAT((TRIM(LEADING '$' FROM invoices.totalprice) / SUM(lineitems.quantity)), 2) AS avgunitrevenue
FROM clients
INNER JOIN invoices ON clients.id = invoices.clientid
INNER JOIN lineitems ON invoices.id = lineitems.invoiceid
WHERE (lineitems.invoiceid = invoices.id) AND invoices.orderdate BETWEEN '".$revenuefrom."' AND '".$revenueto."' AND invoices.stagestatus IN (". implode(',', array_map(function($item) {return '"' . $item . '"'; }, $revenue_check)) .")
GROUP BY invoices.id DESC";

該代碼可以正常工作，並按invoices.id對所有數據進行分組。 但是，項目需求已調整，現在所有內容都必須按invoices.company分組。 當我只是嘗試按invoices.company而不是invoices.id分組時，我的表已完成，但每個公司行的值都非常不准確（沒有sum（）正確）。

建表的PHP CODE：

$result = $conn->query($sql);


    echo "<table id='revenueReportA' align='center' class='report_DT'>
    <thead>
    <tr>

    <th>Customer</th>
    <th>Total Revenue</th>
    <th>Total SQ FT</th>
    <th>AVG Revenue Per SQ FT</th>
    <th>Total Number of Units</th>
    <th>AVG Revenue Per Unit</th>
    </tr>
    </head>";


 if ($result = $conn->query($sql)) {

   // fetch associative array 
  while ($row = $result->fetch_assoc()) {

  echo "<tbody>";
  echo "<tr>";
  echo "<td>" . $row['company'] . "</td>";
  echo "<td>" ."$". $row['totalprice'] . "</td>";
  echo "<td>" . $row['sgtotsqft'] ."&nbsp;&nbsp;". "ft<sup>2</sup>". "</td>";
  echo "<td>" ."$". $row['avgsqftrevenue'] . "</td>";
  echo "<td>" . $row['sgtotqty'] . "</td>";
  echo "<td>" ."$". $row['avgunitrevenue'] . "</td>";
  echo "</tr>";
  echo "</tbody>";
  } 

   echo "</table>";

echo "<BR>";

感謝所有幫助。

謝謝，

Answer 1

我遇到了拼寫錯誤和格式問題。 通過格式化最終數據而不是在嵌入式SELECT語句中進行格式化，我的表數據是准確的。

成功的代碼：

$sql = "SELECT x.company, x.stagestatus, x.shippeddate, FORMAT(SUM(x.totprice), 2) as totalprice, FORMAT(SUM(x.sgtotquantity), 2) as sgtotqty, FORMAT(SUM(x.sgtotalsqft), 2) as sgtotsqft, FORMAT(SUM(x.avgsqftrev), 2) as avgsqftrevenue, FORMAT(SUM(x.avgunitrev), 2) as avgunitrevenue FROM (SELECT t1.company, t1.stagestatus, t1.shippeddate, t1.id, TRIM(LEADING '$' FROM t1.totalprice) AS totprice, t2.invoiceid, SUM(t2.quantity) AS sgtotquantity, SUM(t2.width * t2.height * t2.quantity ) /144 AS sgtotalsqft, (TRIM(LEADING '$' FROM t1.totalprice)/(SUM(t2.width * t2.height * t2.quantity ) /144)) as avgsqftrev, (TRIM(LEADING '$' FROM t1.totalprice) / SUM(t2.quantity)) AS avgunitrev
FROM invoices AS t1 INNER JOIN lineitems AS t2 ON t1.id = t2.invoiceid
WHERE (t2.invoiceid = t1.id)
GROUP BY t1.id) x
WHERE x.stagestatus='Complete'
GROUP BY x.company ASC";

謝謝！！！