使用q框架對多個GET請求進行Node.js遞歸調用

Question

在搜索stackoverflow和Q文檔后，不幸的是我仍然不了解q.ninvoke函數。 我想知道是否有人可以向我解釋它如何與我的方案一起工作：

我正在獲取fetchXml請求的結果，該請求最多返回5000個條目。 我想實現一種方法（通過一條鏈）進行自我調用，直到服務器不再響應頁面調度cookie為止。

最后，所有結果都應在遞歸中歸並到遞歸的頂部...

var tryReexecuteForNext5000Entries = function(entitySetName, fetchXml, args){
    var deferred = q.defer();
    var response = args[0];    
    var jsonBody = args[1];
    var fetchXmlPagingCookieResponse = jsonBody["@Microsoft.Dynamics.CRM.fetchxmlpagingcookie"];

    if(!fetchXmlPagingCookieResponse){        
        deferred.resolve(args);
        return deferred.promise;
    }

    var pagingArgs = getPagingArgs(fetchXmlPagingCookieResponse);
    var pageNumber = pagingArgs[0];
    var pagingCookie = transformCookieForFetch(pagingArgs[1]);
    fetchXml = injectPagingArgsIntoFetchXml(fetchXml, pageNumber, pagingCookie);


    getWithFetchXml(entitySetName, fetchXml)        //recursion!
         .done(function(bodyValue){
             args[1].value = args[1].value.concat(jsonBody.value).concat(bodyValue);
             deferred.resolve(args);
        }
        .fail(function(error){
            deferred.reject(error);
        }));

    return deferred.promise;
}

function getWithFetchXml(entitySetName, fetchXml){
    return AuthProvider.retrieveToken()
        .then(createFetchOptions.bind(this, entitySetName, fetchXml))
        .then(addProxyToOptions)
        .then(executeRequest)
        .then(checkResponse)
        .then(tryReexecuteForNext5000Entries.bind(this, entitySetName, fetchXml))
        .then(onRequestSucceeded.bind(this, "successfully GET fetchXml against CRM"))
        .fail(onFail.bind(this, "webApiRequest.getWithFetchXml: failed to GET with fetchXml: \r\n"+fetchXml));
}

使用此設置Q會拋出“ TypeError：無法讀取未定義的屬性'apply'”

應該如下工作：

• 調用getWithFetchXml
• 檢索JsonObject List1和分頁令牌AND
• ===呼叫getWithFechXml²
• ===檢索JsonObject List2和pageingToken AND
• ======調用getWithFetchXml³
• ======檢索沒有分頁令牌的JsonObject List3
• ======返回列表
• ===將List3追加到List2並返回
• 將List2附加到List1並返回

Answer 1

這是一個愚蠢的語法錯誤...抱歉，開發JavaScript時，我沒有設置VisualStuidoCode以獲得良好的反饋。

問題是：

getWithFetchXml(entitySetName, fetchXml)        //recursion!
        .done(function(bodyValue){
             args[1].value = jsonBody.value.concat(bodyValue);
             deferred.resolve(args);
        }
        .fail(function(error){
            deferred.reject(error);
        }));

錯誤的支架！ 應該：

getWithFetchXml(entitySetName, fetchXml)        //recursion!
            .then(function(bodyValue){
                 args[1].value = jsonBody.value.concat(bodyValue);
                 deferred.resolve(args);
            })
            .fail(function(error){
                deferred.reject(error);
            });

這是我在Node.js中遞歸JavaScript的運行代碼：

function getWithFetchXml(entitySetName, fetchXml){
    return getWithFetchXmlRecursive(entitySetName, fetchXml, null);
}

var getWithFetchXmlRecursive = function(entitySetName, fetchXml, page){
    return AuthProvider.retrieveToken()
        (...)
        .then(tryReexecuteForNext5000Entries.bind(this, entitySetName, fetchXml, page))
        .then(onRequestSucceeded.bind(this, "successfully GET fetchXml against CRM"))
        .fail(onFail.bind(this, "webApiRequest.getWithFetchXml: failed to GET with fetchXml: \r\n"+fetchXml));
}

var tryReexecuteForNext5000Entries = function(entitySetName, fetchXml, page, args){
    (...)
    var fetchXmlPagingCookieResponse = jsonBody["@Microsoft.Dynamics.CRM.fetchxmlpagingcookie"];        
    var onRecursionSucceeded = function(bodyValue){
        args[1].value = jsonBody.value.concat(bodyValue);
        deferred.resolve(args);
    }
    var onRecursionFailed = function(error){deferred.reject(error);};

    if(!fetchXmlPagingCookieResponse){        
        deferred.resolve(args);
        return deferred.promise;
    }
    (...)
    console.log("webApiRequest.tryReexecuteForNext5000Entries: there is more! starting recursive request with depth: " + (page-1));
    getWithFetchXmlRecursive(entitySetName, fetchXml, ++page)        //recursion!
        .then(onRecursionSucceeded)
        .fail(onRecursionFailed);

    return deferred.promise;
}