檢查整行是否存在

Question

我想知道我的代碼出了什么問題。我想做的是在插入數據之前將數據發布到數據庫中，檢查是否存在EQUAL行，如果存在則顯示一條消息。

這是我在頁面頂部的查詢：

if(isset($_POST['submitAddEvents'])){

    // Verify if the data exists
    if(!filter_var($_POST['teamA'] && $_POST['teamB'] && $_POST['eventDate'])){
        $stmt = $db->prepare('SELECT * FROM events WHERE teamA = :teamA AND teamB = :teamB AND eventDate = :eventDate');
        $stmt->execute(array(
            ':teamA' => $_POST['teamA'],
            ':teamB' => $_POST['teamB'],
            ':eventDate' => $_POST['eventDate'],
        ));
        $row = $stmt->fetch(PDO::FETCH_ASSOC);
    }

    $statement = $db->prepare("INSERT INTO events(teamA, teamB, eventDate, `time`, live) VALUES (:teamA, :teamB, :eventDate, :timeOfEvent, :live)");
    $statement->execute(array(
        ':teamA' => $_POST['teamA'],
        ':teamB' => $_POST['teamB'],
        ':eventDate' => $_POST['date'],
        ':timeOfEvent' => $_POST['timeOfEvent'],
        ':live' => $_POST['live'],
    ));
    $id = $db->lastInsertId('ID');
}
?>

這是頁面底部的腳本：

<script>
    //Saving Data
    $('#saveButton').click(function(){
        var teamA = $('#teamA').val();
        var teamB = $('#teamB').val();
        var date = $('#date').val();
        var timeOfEvent = $('#timeOfEvent').val();
        var live = "0";
        if($("#live").is(':checked'))
            live = $('#live').val();

        $.ajax({
            url  : "<?= $_SERVER['PHP_SELF'] ?>",
            type : "POST",
            async: false,
            data :
            {
                'submitAddEvents' : 1,
                'teamA' : teamA,
                'teamB' : teamB,
                'date' : date,
                'timeOfEvent' : timeOfEvent,
                'live' : live,
            },
            success:function(re)
            {
                    window.location = "addEvents.php";
            }
        });
    });
    </script>

但是沒有用，數據保存到數據庫中，並且沒有通過ajax提交的任何驗證...有人可以告訴我這是怎么回事嗎？ 有人可以幫我解決嗎？

Answer 1

您將獲得現有行$row = $stmt->fetch(PDO::FETCH_ASSOC); 但是你什么也沒做。 使用if ($stmt->rowCount() == 0)檢查行數是否為零，然后執行其余代碼並插入數據。

Answer 2

如果需要從服務器端顯示ajax響應。 您只是在服務器端回顯任何內容。 您將在ajax成功alert(re);收到該消息alert(re); 像這樣

阿賈克斯：

success:function(re)
        {
              alert(re); //here you get the message from server side 

                window.location = "addEvents.php";
        }

PHP：

在PHP中，您必須添加條件條件來檢查數據是否重復或不這樣

<?php

    if(isset($_POST['submitAddEvents'])){

        // Verify if the data exists
        if(!filter_var($_POST['teamA'] && $_POST['teamB'] && $_POST['eventDate'])){
            $stmt = $db->prepare('SELECT * FROM events WHERE teamA = :teamA AND teamB = :teamB AND eventDate = :eventDate');
            $stmt->execute(array(
                ':teamA' => $_POST['teamA'],
                ':teamB' => $_POST['teamB'],
                ':eventDate' => $_POST['eventDate'],
            ));
            $row = $stmt->fetch(PDO::FETCH_ASSOC);

        if ($stmt->rowCount()==0)
        {



            $statement = $db->prepare("INSERT INTO events(teamA, teamB, eventDate, `time`, live) VALUES (:teamA, :teamB, :eventDate, :timeOfEvent, :live)");
            $statement->execute(array(
            ':teamA' => $_POST['teamA'],
            ':teamB' => $_POST['teamB'],
            ':eventDate' => $_POST['date'],
            ':timeOfEvent' => $_POST['timeOfEvent'],
            ':live' => $_POST['live'],
            ));
            $id = $db->lastInsertId('ID');

            echo "inserted succesfully ";


        }
        else
        {


            echo "not inserted because data duplicate";
        }

       }

    }
    ?>

Answer 3

單獨頁面上的PHP應該看起來更像：

<?php
if(isset($_POST['submitAddEvents'])){
  // obviously these other things are also already set unless there's a hack
  $tA = trim($_POST['teamA']); $tB = trim($_POST['teamA']);
  $eD = trim($_POST['eventDate']); $tE = trim($_POST['timeOfEvent']);
  $lV = trim($_POST['live']);
  // Verify if the data exists
  if($ta !== '' && $tB !== '' && $eD !== '' && $tE !== '' && $lV !== ''){
    // I like to save steps
    $db->query("INSERT events (teamA, teamB, eventDate, `time`, live) VALUES ('$tA', '$tB', '$eD', '$tE', '$lV')");
  }
  // doesn't look like you need to query the information you just entered - code above assumes STRING like data in MySQL, which may not be the case since we can't see your database
}
?>