調用未定義的方法CI_DB_mysqli_driver :: result（）

Question

我的模型錯誤：調用未定義的方法CI_DB_mysqli_driver :: result（）

     <?php
     defined('BASEPATH') OR exit('No direct script access allowed');

     class teacher_feedback extends CI_Model {

     public function teacher_feedback_query($teacher)
      {
    $teacher_feedback_query = 'SELECT TD.name, TD.subject, TFA.answer_value,    SBI.first_name, TFSAC.comment, TFSC.comment, TFQ.teachers_feedback_question_id FROM teacher_details as TD inner join teachers_feedback_student_answer as TFSA on TFSA.teacher_id = TD.teacher_id inner join  teachers_feedback_answer as TFA on TFA.teachers_feedback_answer_id = TFSA.teachers_feedback_answer_id inner join teachers_feedback_student_answer_comment as TFSAC on TFSAC.teacher_id = TD.teacher_id inner join student_basic_info as SBI on SBI.student_id=TFSAC.student_id inner join teachers_feedback_student_comment as TFSC on TFSC.student_id = SBI.student_id inner join teachers_feedback_question as TFQ on TFQ.teachers_feedback_question_id = TFSA.teachers_feedback_question_id  where TD.teacher_id = ?';

$teacher_query = $this->db->query($teacher_feedback_query,array($teacher));
$teacher_feedback_result = $this->db->result($teacher_query);
return $teacher_feedback_result();
}
}
?>

Answer 1

嘗試返回result_array（）而不是僅返回result（）

Answer 2

我認為您在這里嘗試做的是錯誤的。 應該對查詢結果而不是在db對象上調用result方法。

嘗試這個：

<?php

defined('BASEPATH') OR exit('No direct script access allowed');

class teacher_feedback extends CI_Model {

     public function teacher_feedback_query($teacher)
     {
          $teacher_feedback_query = 'SELECT TD.name, TD.subject, TFA.answer_value,    SBI.first_name, TFSAC.comment, TFSC.comment, TFQ.teachers_feedback_question_id FROM teacher_details as TD inner join teachers_feedback_student_answer as TFSA on TFSA.teacher_id = TD.teacher_id inner join  teachers_feedback_answer as TFA on TFA.teachers_feedback_answer_id = TFSA.teachers_feedback_answer_id inner join teachers_feedback_student_answer_comment as TFSAC on TFSAC.teacher_id = TD.teacher_id inner join student_basic_info as SBI on SBI.student_id=TFSAC.student_id inner join teachers_feedback_student_comment as TFSC on TFSC.student_id = SBI.student_id inner join teachers_feedback_question as TFQ on TFQ.teachers_feedback_question_id = TFSA.teachers_feedback_question_id  where TD.teacher_id = ?';

          $teacher_query = $this->db->query($teacher_feedback_query,array($teacher));
          //$teacher_feedback_result = $this->db->result($teacher_query);
          $teacher_feedback_result = $teacher_query->result();
          return $teacher_feedback_result; // Remove parenthesis, $teacher_feedback_result is not a function
     }
}

?>

編輯：

關於錯誤調用未定義的方法CI_DB_mysqli_driver :: result（）

PHP拋出此錯誤，因為CodeIgniter MySQLi適配器類沒有方法result 。 這是CodeIgniter MySQLi驅動程序類。 您可以檢查它，沒有這樣的方法result ：

https://github.com/bcit-ci/CodeIgniter/blob/develop/system/database/drivers/mysqli/mysqli_driver.php

因此，當您調用$this->db->result($teacher_query) ， $this->db附加到CI_DB_mysqli_driver ，因此您收到錯誤消息，即正在調用未定義的方法。

Answer 3

大多數情況下，由於我們在上面應用了核心php代碼，而ci有自己的方式來應用此錯誤，因此會出現此類錯誤。 因此，有時我們成功地應用了一些核心代碼，但有時卻沒有。 在這種情況下，請嘗試繼續使用ci doc，您很可能會找到解決方案。 祝好運。