![](/img/trans.png)
[英]SQLite - Output count of all records per day including days with 0 records
[英]SQL count per day and add together all following days
我正在嘗試編寫一個 SQL 查詢來計算每天的用戶並將結果加在一起。 我被卡住了,因為我不知道如何動態地將結果加在一起。
桌子:
UserId | CreateDate
-------+----------------------------
1 | 2016-06-23 13:59:24.0000000
2 | 2016-06-23 15:59:24.0000000
3 | 2016-06-24 05:59:24.0000000
...
我有以下查詢來計算每天的注冊量。
SELECT
CONVERT(date, u.CreateDate) as [Date], Count(UserId) as [Count]
FROM
User as u
GROUP BY
CONVERT(date, u.CreateDate)
ORDER BY
[Date]
我不知道如何將結果相加。 我希望 SQL Server 2008 R2 有一個內置的 function 適合我的情況。 還是我需要創建臨時表?
假設第 1 天有 2 個注冊,第 2 天有 1 個注冊,第 3 天有 4 個注冊,我想收到這樣的結果:
2016-06-23 | 2
2016-06-24 | 2 + 1 = 3
2016-06-25 | 3 + 4 = 7
我需要一個動態解決方案,因為查詢將有另一個日期限制 => Where CreateDate bewteen x 和 y。
謝謝魯迪
您可以使用sum
窗口函數來獲取運行總計。
select [Date],sum([Count]) over(order by [Date])
from (SELECT CONVERT(date, u.CreateDate) as [Date], Count(UserId) as [Count]
FROM User as u
GROUP BY CONVERT(date, u.CreateDate)
) x
order by 1
添加一個where
子句以過濾內部查詢中的特定日期范圍。
使用紅移數據庫
select [Date],sum([Count]) over(order by [Date] ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW)
from (SELECT CONVERT(date, u.CreateDate) as [Date], Count(UserId) as [Count]
FROM User as u
GROUP BY CONVERT(date, u.CreateDate)
) x
order by 1
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.