[英]XSLT 1.0 transformation overwrite or add child nodes
我正在嘗試在以下xml上使用xslt 1.0(使用Visual Studio 2015)轉換。
我得到了房屋的名稱,以及應該在該房屋內的家具的名稱和新值。
如果已經存在具有給定名稱的家具,請覆蓋其值。
如果沒有,請創建一個新的。
如果家具在屋子里但不應該被覆蓋,只需復制它即可。
房屋中已擺放的家具的順序不應更改。
我對c ++,C#,JAVA之類的語言並不陌生,但是xslt是...不同。 盡管這是上述語言中的一項簡單任務,但我在這里確實很努力。
請幫忙。
XML代碼
<Street>
<House Name="house1">
<Window>niceView</Window>
<Furniture Name="name1">value1</Furniture>
<Furniture Name="name2">value2</Furniture>
<Furniture Name="name3">value3</Furniture>
<Furniture Name="name4">value4</Furniture>
</House>
<House>
<Brick Name="cubrick"></Brick>
<Furniture name="name1>value</Furniture>
</House>
</Street>
XSLT開始
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:param name="house1" select='house1'/>
<xsl:param name="name2" select='newValue1'/>
<xsl:param name="name4" select='newValue2'/>
<xsl:param name="name10" select='newValue5'/>
...
所需的輸出是:
<Street>
<House Name="house1">
<Window>niceView</Window>
<Furniture Name="name1">value1</Furniture>
<Furniture Name="name2">newValue1</Furniture>
<Furniture Name="name3">value3</Furniture>
<Furniture Name="name4">newValue2</Furniture>
<Furniture Name="name10">newValue5</Furniture>
</House>
<House>
<Brick Name="cubrick"></Brick>
<Furniture name="name1>value</Furniture>
</House>
</Street>
根據您的意見,我建議您考慮采用以下方法:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:exsl="http://exslt.org/common"
extension-element-prefixes="exsl">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- MODIFY THESE AS NECESSARY -->
<xsl:param name="my-house">house1</xsl:param>
<xsl:variable name="my-values">
<Furniture Name="name2">newValue2</Furniture>
<Furniture Name="name4">newValue4</Furniture>
<Furniture Name="name10">newValue10</Furniture>
</xsl:variable>
<!-- DO NOT MODIFY FROM THIS POINT ON -->
<xsl:variable name="user-values" select="exsl:node-set($my-values)/Furniture" />
<!-- identity transform -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="House">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
<xsl:if test="@Name=$my-house">
<!-- add missing nodes -->
<xsl:copy-of select="$user-values[not(@Name=current()/Furniture/@Name)]"/>
</xsl:if>
</xsl:copy>
</xsl:template>
<xsl:template match="Furniture">
<xsl:variable name="override" select="$user-values[@Name=current()/@Name]"/>
<Furniture Name="{@Name}">
<xsl:choose>
<xsl:when test="../@Name=$my-house and $override">
<xsl:value-of select="$override" />
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="." />
</xsl:otherwise>
</xsl:choose>
</Furniture>
</xsl:template>
</xsl:stylesheet>
當應用於以下格式正確的(!)示例輸入時:
XML格式
<Street>
<House Name="house1">
<Window>niceView</Window>
<Furniture Name="name1">value1</Furniture>
<Furniture Name="name2">value2</Furniture>
<Furniture Name="name3">value3</Furniture>
<Furniture Name="name4">value4</Furniture>
</House>
<House>
<Brick Name="cubrick"></Brick>
<Furniture Name="name1">value</Furniture>
</House>
</Street>
結果將是:
<?xml version="1.0" encoding="UTF-8"?>
<Street>
<House Name="house1">
<Window>niceView</Window>
<Furniture Name="name1">value1</Furniture>
<Furniture Name="name2">newValue2</Furniture>
<Furniture Name="name3">value3</Furniture>
<Furniture Name="name4">newValue4</Furniture>
<Furniture Name="name10">newValue10</Furniture>
</House>
<House>
<Brick Name="cubrick"/>
<Furniture Name="name1">value</Furniture>
</House>
</Street>
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