Python 3.5中的Request，urlopen中的禁止（403）錯誤

Question

我正在嘗試使用以下代碼在Python 3.5中訪問URL http://learncodethehardway.org/words.txt ，但看到403 HTTP錯誤。 我應該如何配置headers以避免這種情況？

import urllib.request
url = "http://learncodethehardway.org/words.txt"

hdr = {'User-Agent': 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.64 Safari/537.11',
  'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8',
  'Accept-Charset': 'ISO-8859-1,utf-8;q=0.7,*;q=0.3',
  'Accept-Encoding': 'none',
  'Accept-Language': 'en-US,en;q=0.8',
  'Connection': 'keep-alive'}
req = urllib.request.Request(url, None, headers=hdr)
html = urllib.request.urlopen(req)

print (html.read())

Answer 1

這對我有用：

import urllib.request
url = 'http://learncodethehardway.org/words.txt'
req = urllib.request.Request(url, headers={'User-Agent': 'Mozilla/5.0'})
html = urllib.request.urlopen(req).read()
print(html.decode())

有關更多信息，請參見類似的問題： Python 3 Web Scraping中的HTTP錯誤403